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2 years ago

If 3 - 2x = 13, then x = -5.

Mathematics

2 answers:

vlada-n [284]2 years ago

5 0

Answer:

True

Step-by-step explanation:

I did the math

Svetach [21]2 years ago

5 0

Step-by-step explanation:

to prove= Rhs= x=-5

Lhs=3-2x=13

= -2x=13-3

=x=10/-2

x=-5

hence proved

LHS=RHS

hope this helps

please mark as brainliest:)

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Answer:

40 coats don't have hoods

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2 years ago

Factor completely 4x2 − 8x − 60. (4x − 20)(x + 3) 4(x − 5)(x + 3) (4x − 4)(x + 15) 4(x − 1)(x + 15)

katovenus [111]

after complete factorization of $4x^2-8x-60$ the answer is $4(x+3)(x-5)$

Step-by-step explanation:

We need to factor $4x^2-8x-60$

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3 years ago

Solve 4x + 11 = k for x.

steposvetlana [31]

Answer:

Step-by-step explanation:

Simplifying

4x + 11 = k

Reorder the terms:

11 + 4x = k

Solving

11 + 4x = k

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-11' to each side of the equation.

11 + -11 + 4x = -11 + k

Combine like terms: 11 + -11 = 0

0 + 4x = -11 + k

4x = -11 + k

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Simplifying

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2 years ago

Simplify 3x -5 + 25x-9

mash [69]

Answer:

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Step-by-step explanation:

3x - 5 + 25x - 9

= 28x - 14

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2 years ago

Read 2 more answers

I need help 6x-2y=10 x-2y=-5 solve by elimination

dem82 [27]

<h3><u>Explanation</u></h3>

Given the system of equations.

$\begin{cases} 6x - 2y = 10 \\ x - 2y = - 5 \end{cases}$

Solve the system of equations by eliminating either x-term or y-term. We will eliminate the y-term as it is faster to solve the equation.

To eliminate the y-term, we have to multiply the negative in either the first or second equation so we can get rid of the y-term. I will multiply negative in the second equation.

$\begin{cases} 6x - 2y = 10 \\ - x + 2y = 5 \end{cases}$

There as we can get rid of the y-term by adding both equations.

$(6x - x) + ( - 2y + 2y) = 10 + 5 \\ 5x + 0 = 15 \\ 5x = 15 \\ x = \frac{15}{5} \longrightarrow \frac{ \cancel{15}}{ \cancel{5}} = \frac{3}{1} \\ x = 3$

Hence, the value of x is 3. But we are not finished yet because we need to find the value of y as well. Therefore, we substitute the value of x in any given equations. I will substitute the value of x in the second equation.

$x - 2y = - 5 \\ 3 - 2y = - 5 \\ 3 + 5 = 2y \\ 8 = 2y \\ \frac{8}{2} = y \\ y = \frac{8}{2} \longrightarrow \frac{ \cancel{8}}{ \cancel{2}} = \frac{4}{1} \\ y = 4$

Hence, the value of y is 4. Therefore, we can say that when x = 3, y = 4.

Answer Check by substituting both x and y values in both equations.

<u>First</u><u> </u><u>Equation</u>

$6x - 2y = 10 \\ 6(3) - 2(4) = 10 \\ 18 - 8 = 10 \\ 10 = 10 \longrightarrow \sf{true} \: \green{ \checkmark}$

<u>Second</u><u> </u><u>Equation</u>

$x - 2y = - 5 \\ 3 - 2(4) = - 5 \\ 3 - 8 = - 5 \\ - 5 = - 5 \longrightarrow \sf{true} \: \green{ \checkmark}$

Hence, both equations are true for x = 3 and y = 4. Therefore, the solution is (3,4)

<h3><u>Answer</u></h3>

$\begin{cases} x = 3 \\ y = 4 \end{cases} \\ \sf \underline{Coordinate \: \: Form} \\ (3,4)$

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3 years ago