Answer:
2
Step-by-step explanation:
Given the data : 29, 2, 28, 30, 26, 31
Outlier ;
Lower :Q1 - (1.5 * IQR)
Upper : Q3 + (1.5 * IQR)
Q1 = Lower quartile ; Q3 = upper quartile ; IQR = Interquartile range
Using calculator :
Q1 = 26
Q3 = 30
IQR = (Q3 - Q1) = 30 - 26 = 4
Lower : 26 - (1.5 * 4) = 20
Upper : 30 + (1.5 * 4) = 36
Hence, the number in the given data which falls outside the range is 2
The answer is A, the denominator should be 18.
Answer:
n = 8
Step-by-step explanation:
-7n² = -448
=> n² = -448 / -7
=> n² = 64
=> n = 
=> n = 8
Hope it helps :)
Please mark my answer as the brainliest
PEMDAS
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction
Use these in order to get the correct answer.