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Nookie1986 [14]
2 years ago
14

15 decreased by the product of a number x and 4 is 8

Mathematics
1 answer:
Alisiya [41]2 years ago
7 0

Answer:

Step-by-step explanation:

product= multiply

x*4=8 aka 8/4=2

so x=2

15-8=7

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X=5 and y=7 for algebraic expression 2(4x-3) + 6(3y-5)
garik1379 [7]

Answer:

130

Step-by-step explanation:

2(4x - 3) + 6(3y - 5)

2(4 × 5 - 3) + 6(3 × 7 - 5)

2(20 - 3) + 6(21 - 5)

2(17) + 6(16)

34 + 96

130

8 0
3 years ago
Read 2 more answers
A cylinder has a radius of 40 ft and a height of 17 ft. What is the exact surface area of the cylinder?
Georgia [21]

we know that

surface area of the cylinder=2*{area of the base}+perimeter of base*height

area of the base=pi*r²

r=40 ft

Area of base=pi*40²

Area of the base=1600*pi ft²


Perimeter of the base=2*pi*r

Perimeter of the base=2*pi*40

Perimeter of the base=80*pi ft


surface area of the cylinder=2*1600*pi+80*pi*17

surface area=4560*pi ft²


therefore

the answer is the option

4560π ft2

8 0
3 years ago
Read 2 more answers
Maggie is rock climbing. After reaching the summit, she descends 14 feet in 2 1/3 minutes. If she continues at this rate, where
attashe74 [19]
Steps:
2 1/3 * 3 = 7
14 * 3 = 42
42 divided by 7 = 6
6 * 8 = 48
So, Maggie is 48 feet under the summit (-48). Therefore, the correct answer is d.
4 0
3 years ago
6.12 fraction equivalent
trapecia [35]
It’s 6 3/25 as a fraction
7 0
3 years ago
Read 2 more answers
6) John purchased 120 shares of Walmart stock at $58.02 each. He sold the stock for $120.98.
antiseptic1488 [7]

Answer:

John lost $6841.42.

Step-by-step explanation:

Let's find out how much John paid for the stock he bought.  Each share cost $58.02. He bought 120 shares.  Multiply the price by the number of shares.

58.02 x 120 = 6962.40

He sold the stock for $120.98 -- a huge loss!  (We are not told that the $120.98 is the selling price of one share, so I'm assuming that's what John sold all his shares for.)

Find the difference to see what his loss was.

$6962.40 - $120.98 = $6841.42 LOST!

8 0
3 years ago
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