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andreev551 [17]
3 years ago
11

How to find the point of intersection algebraically?

Mathematics
1 answer:
alexdok [17]3 years ago
7 0
You use substitution or elimination.
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The steps to derive the quadratic formula are shown below:
prohojiy [21]

Answer:

\huge\boxed{\sf Option \ B}

Step-by-step explanation:

<h3>Step 3:</h3>

\displaystyle x^2+\frac{bx}{a} =\frac{-c}{a} --------------------(1)

<h3>The next step will be:</h3>
  • to find the b² for the expression on the left.
<h3>How to find b²:</h3>

Take the expression

\displaystyle x^2 + \frac{bx}{a}

<u>We can also write it as:</u>

\displaystyle (x)^2 + 2(x)(\frac{b}{2a} )

According to the formula a^2+2ab+b^2, the b of this expression is \displaystyle \frac{b}{2a}. So,

b² will be:

\displaystyle =(\frac{b}{2a} )^2\\\\=\frac{b^2}{4a^2}

So, we will add \displaystyle \frac{b^2}{4a^2} to both sides in Eq. (1)

For STEP 4, the equation will become:

\displaystyle x^2+\frac{bx}{a} + \frac{b^2}{4a^2} = \frac{-c}{a} + \frac{b^2}{4a^2}

\rule[225]{225}{2}

7 0
1 year ago
Read 2 more answers
What is 72 degrees + [x+15 degrees]??
a_sh-v [17]
I'm pretty sure it would just be 87+x degrees right?
3 0
3 years ago
What is the initial value in the equation f(x) = 350(1 - 0.12)^x? *
kvasek [131]

Given:

The function is:

f(x)=350(1-0.12)^x

To find:

The initial value of the function.

Solution:

We have,

f(x)=350(1-0.12)^x

The value of the function at x=0 is called the initial value of the function.

For x=0, we get

f(0)=350(1-0.12)^0

f(0)=350(0.88)^0

Clearly 0.88 is a non zero number and zero to the power of a non zero number is always 1.

f(0)=350(1)

f(0)=350

Therefore, the initial value of the function is 350.

5 0
3 years ago
What is 6/10 simplified
Komok [63]
6/10 = 3/5

Simply divide the numerator and denominator of 6/10 by 2. 6/10 is the same as 3/5.
5 0
3 years ago
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Someone please help me!!!!!!!
Usimov [2.4K]

Step-by-step explanation:

In the second step while opening the bracket, instead of 'a', there should be - 4a.

5 0
3 years ago
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