We will have a system of equations, and we are going to solve it by using substitution.
Let's make the equations.
x+y+z=2100
z+y=x
Since y and z are equal, I think it is easier for us to have them as one variable for now. Let the value of z and y be a.
These are the equations now.
x+2a=2100
2a=x
Since the second equation is giving the value of x, let it replace the value of x also in the first equation.
2a+2a=2100
4a=2100
2100÷4= 525
so, x and y equal 525. Let's put this in our original equation.
x+525+525=2100
x+ 1,050= 2,100
x= 1,050
So, x=1,050, y= 525 =z.
Try 3.14x2= 6.28 im so sorry if its wrong
I think that the answer is f...
Answer:
11.20
Step-by-step explanation:
Multiply both equations by 100:
19.99=1999
8.79=879
1999-879=1120
Divide by 100:
1120/100=11.20 saved ................
Answer: Joe has 20 remaining apples
[to get your answer, subtract, 35 - 5 - 5 - 5]