There are 2 tangent lines that pass through the point

and

Explanation:
Given:

The point-slope form of the equation of a line tells us that the form of the tangent lines must be:
![[1]](https://tex.z-dn.net/?f=%5B1%5D)
For the lines to be tangent to the curve, we must substitute the first derivative of the curve for
:



![[2]](https://tex.z-dn.net/?f=%5B2%5D)
Substitute equation [2] into equation [1]:
![[1.1]](https://tex.z-dn.net/?f=%5B1.1%5D)
Because the line must touch the curve, we may substitute 

Solve for x:




± 
±
<em> </em>

There are 2 tangent lines.

and

Let's start with m∠1. m∠1 <em>has </em>to be 90º because line segment AB is perpendicular with line segment AC, as it shows a right angle symbol on the angle beside m∠1. Now that we know that, it will be much easier to find m∠2 and m∠3 because m∠1, m∠2 and m∠3 are part of the triangle formed in the middle, and all angles in a triangle add up to 180º. 180-90 is 90, therefore, m∠2 +m∠3=90º so all three angles add up to 180º. You don't even have to find the specific angle measurements.
Hope this helps. I also attached a (rather poorly edited) image.
I3/I6(8O)= 65m of electrical cable left