![\bf \textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \qquad center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad radius=\stackrel{}{ r}\\\\ -------------------------------\\\\ (x-3)^2+(y+7)^2=64\implies [x-\stackrel{h}{3}]^2+[y-(\stackrel{k}{-7})]^2=\stackrel{r}{8^2} \\\\\\ center~(3,-7)\qquad radius=8](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bequation%20of%20a%20circle%7D%5C%5C%5C%5C%20%0A%28x-%20h%29%5E2%2B%28y-%20k%29%5E2%3D%20r%5E2%0A%5Cqquad%20%0Acenter~~%28%5Cstackrel%7B%7D%7B%20h%7D%2C%5Cstackrel%7B%7D%7B%20k%7D%29%5Cqquad%20%5Cqquad%20%0Aradius%3D%5Cstackrel%7B%7D%7B%20r%7D%5C%5C%5C%5C%0A-------------------------------%5C%5C%5C%5C%0A%28x-3%29%5E2%2B%28y%2B7%29%5E2%3D64%5Cimplies%20%5Bx-%5Cstackrel%7Bh%7D%7B3%7D%5D%5E2%2B%5By-%28%5Cstackrel%7Bk%7D%7B-7%7D%29%5D%5E2%3D%5Cstackrel%7Br%7D%7B8%5E2%7D%0A%5C%5C%5C%5C%5C%5C%0Acenter~%283%2C-7%29%5Cqquad%20radius%3D8)
so, the broadcast location and range is more or less like the picture below.
Difference between the area of the triangle and square is 25
Step-by-step explanation:
- Step 1: Find the area of the triangle given its 3 sides using the Heron's formula.
Area of the triangle =
where s = 
⇒ s = (6 + 8 + 10)/2 = 24/2 = 12
= 
=
=
= 24 sq. units
- Step 2: Find the area of the square with perimeter = 28 units.
Perimeter of the square = 4 × side = 28
⇒ Side of the square = 28/4 = 7 units
⇒ Area of the square = (side)² = 7² = 49 sq. units
- Step 3: Find the difference between the area of the square and triangle.
Difference = 49 - 24 = 25
Answer: C. 180 times
Step-by-step explanation:
From the 60 trials, the percentage of times Laura picked a green marble was:
= 100% - Percentage of times blue and red were picked
= 100% - 25% - 15%
= 60%
If these results were repeated with 300 trials, the number of times Laura would be expected to pick green would be:
= 60% * 300
= 180 times
2.25*x=10
Which x is the number of books purchased
Solve for x
X=10÷2.25
X=4.44