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3 years ago

15

Which of the following expressions has a coefficient of 6 and a constant of 9?

2 answers:

Tcecarenko [31]3 years ago

6 0

It would be C because a coefficient is always with a variable and 6 is with a variable which makes it a coefficient

Hope this helps

Have a great day/night

Liula [17]3 years ago

6 0

Answer:

6x+9

Step-by-step explanation:

i just took the iready, and i got it wrong and it showed this as the answer.

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Hoochie [10]

Answer:

1) 40 degrees

2) 140 degrees

3) 110 degrees

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5) 70 degrees

Explanation:

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3 years ago

What is the exact volume of the cylinder?

Romashka-Z-Leto [24]

Π r² h
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2 years ago

Arithmetic sequences et sn} be an arithmetic sequence that starts with an initial index of 0. The initial term is 3 and the comm

navik [9.2K]

Answer:

(a) The value of $s_z$ is (z+1)(3-z).

(b) The next term in the sequence is -2.

Step-by-step explanation:

(a)

It is given that arithmetic sequence that starts with an initial index of 0.

The initial term is 3 and the common difference is -2.

$a_0=3$

$d=-2$

We need to find the value of $s_z$ .

$s_z=\sum_{n=0}^{n=z}(a+nd)$

where, a is initial term and d is common difference.

$s_z=\sum_{n=0}^{n=z}(3-2n)$

The sum of an arithmetic sequence with initial index 0 is

$s_n=\frac{n+1}{2}[2a+nd]$

where, a is initial term and d is common difference.

Substitute n=z, a=3 and d=-2 in the above formula.

$s_z=\frac{z+1}{2}[2(3)+z(-2)]$

$s_z=\frac{z+1}{2}[2(3-z)]$

$s_z=(z+1)(3-z)$

Therefore the value of $s_z$ is (z+1)(3-z).

(b)

The given arithmetic sequence is

7, 4, 1, ...

We need to find the term in the sequence.

In the given arithmetic sequence the first term is

$a=7$

The common difference of the sequence is

$d=a_2-a_1\Rightarrow 4-7=-3$

The first term is 7 and common difference is -3.

Add common difference in last given term, i.e., 1, to find the next term of the sequence.

$1+(-3)=1-3=-2$

Therefore the next term in the sequence is -2.

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4 years ago

In trapiziod ABCD with bases AB and DC , diagonals intersect at point O. Find the length of diagonal BD, if BO=6 cm and A/O=3/1

ElenaW [278]

Answer:

the length of the diagonal BD is 8 cm

Step-by-step explanation:

The computation of the length of diagonal BD is as follows

Here the trapezoid diagonals divides each other in an equivalent ratio

So, equation would be

AO ÷ OC = OB ÷ OD

Now put there values to the above equation

3 ÷ 1 = 6 ÷ OD

3OD = 6

Now divided it by 3 in both the sides

OD = 2

Now the BD would be

= BO + OD

= 6 + 2

= 8 cm

hence, the length of the diagonal BD is 8 cm

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3 years ago

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Aneli [31]

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Step-by-step explanation: All of them increase the price.

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3 years ago

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