Question

Question 7 of 10 What is the sum of the first five terms of a geometric series with a1 = 10 and r = 1/5?​

Answer 1

Answer:

12.496

Step-by-step explanation:

$\text{Sum}=\frac{a*(1-r^n)}{1-r}\\\text{Here a=10, r=1/5, plugging them in the above formula we get}\\\text{Sum}=\frac{10*(1-(1/5)^5)}{1-(1/5)}\\\text{Sum}=\frac{1562}{125}=12.496$