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3 years ago

LET R equal the rental fee for one locker write an equation that represents the situation

Mathematics

1 answer:

ohaa [14]3 years ago

5 0

Answer:

R x 1= price of 1 locker

Step-by-step explanation:

it would continue the same way. Just multiply R and the number of lockers.

Is there a certain situation it was asking about?

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A water tank in the shape of a right cylinder has a diameter of 14 feet and a height of 18 feet. What is the volume?

Doss [256]

Volume = (pi 3.14)(r^2)(h)

(3.14)(49)(18)

(153.86)(18)

2769.48

7 0

3 years ago

−3z−z Help pleease i will give u 20 points

MAVERICK [17]

Answer:

-4z is the answer

Step-by-step explanation:

-3z-z

-4z

3 0

2 years ago

Fine length of BC on the following photo.

MrMuchimi

Answer:

$BC=4\sqrt{5}\ units$

Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

Find the length side AC

Applying the Pythagorean Theorem

$AC^2=AD^2+DC^2$

substitute the given values

$AC^2=16^2+8^2$

$AC^2=320$

$AC=\sqrt{320}\ units$

simplify

$AC=8\sqrt{5}\ units$

step 2

In the right triangle ACD

Find the cosine of angle CAD

$cos(\angle CAD)=\frac{AD}{AC}$

substitute the given values

$cos(\angle CAD)=\frac{16}{8\sqrt{5}}$

$cos(\angle CAD)=\frac{2}{\sqrt{5}}$ ----> equation A

step 3

In the right triangle ABC

Find the cosine of angle BAC

$cos(\angle BAC)=\frac{AC}{AB}$

substitute the given values

$cos(\angle BAC)=\frac{8\sqrt{5}}{16+x}$ ----> equation B

step 4

Find the value of x

In this problem

$\angle CAD=\angle BAC$ ----> is the same angle

equate equation A and equation B

$\frac{8\sqrt{5}}{16+x}=\frac{2}{\sqrt{5}}$

solve for x

Multiply in cross

$(8\sqrt{5})(\sqrt{5})=(16+x)(2)\\\\40=32+2x\\\\2x=40-32\\\\2x=8\\\\x=4\ units$

$DB=4\ units$

step 5

Find the length of BC

In the right triangle BCD

Applying the Pythagorean Theorem

$BC^2=DC^2+DB^2$

substitute the given values

$BC^2=8^2+4^2$

$BC^2=80$

$BC=\sqrt{80}\ units$

simplify

$BC=4\sqrt{5}\ units$

7 0

3 years ago

Please help meee! :< An author receives $0.60 for each hardcover book or paperback book that is sold. There were x hardcover

rusak2 [61]

D) 47,000

0.60 (x+38,000)= 51,000
(0.60x)+22,800= 51,000
51,000-22,800= 28,200
28,200÷0.60= 47,000
0.06 (47,000+38,000)= 51,000
28,200+22,800= 51,000

5 0

3 years ago

a small bridge sit atop for cube shaped powers that all have the same volume. The combined volume of the four pillars is 503 how

Natasha_Volkova [10]

Answer:

60 inches long are the sides of the pillars.

Step-by-step explanation:

Given : A small bridge sits atop four cube shaped pillars that all have the same volume. the combined volume of the four pillars is 500 ft cubed.

To find : How many inches long are the sides of the pillars?

Solution :

Refer the attached picture below for Clarence of question.

The volume of the cube is $V=a^3$

Where, a is the side.

The combined volume of the four pillars is 500 ft cubed.

The volume of each cube is given by,

$V=\frac{500}{4}=125\ ft^3$

Substitute in the formula to get the side,

$125=a^3$

$a=\sqrt[3]{125}$

$a=5\ ft$

We know, 1 feet = 12 inches

So, 5 feet = $5\times 12=60$ inches

Therefore, 60 inches long are the sides of the pillars.

6 0

3 years ago