Question

A vertical light pole on a hillside casts a

Answer 1

Answer: $37.4\ m$

Step-by-step explanation:

Given length of shadow $l=55\ m$

Hill inclination $21.4^{\circ}$

Angle of elevation for sun $48.3^{\circ}$

Suppose the length of the pole is $h$

from the figure, and using sine rule. It can written

$\Rightarrow \dfrac{55}{\sin 41.7^{\circ}}=\dfrac{h}{\sin 26.9^{\circ}}\\\\\Rightarrow h=55\cdot\dfrac{\sin 26.9^{\circ}}{\sin 41.7^{\circ}}\\\\\Rightarrow h=55\cdot 0.68011\\\Rightarrow h=37.40\ m$