A vertical light pole on a hillside casts a

Mathematics

1 answer:

Marysya12 [62]2 years ago

5 0

Answer: $37.4\ m$

Step-by-step explanation:

Given length of shadow $l=55\ m$

Hill inclination $21.4^{\circ}$

Angle of elevation for sun $48.3^{\circ}$

Suppose the length of the pole is $h$

from the figure, and using sine rule. It can written

$\Rightarrow \dfrac{55}{\sin 41.7^{\circ}}=\dfrac{h}{\sin 26.9^{\circ}}\\\\\Rightarrow h=55\cdot\dfrac{\sin 26.9^{\circ}}{\sin 41.7^{\circ}}\\\\\Rightarrow h=55\cdot 0.68011\\\Rightarrow h=37.40\ m$

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Min-Jee is planting two rectangular flower beds. One bed is 2.78 feet by 4.81 feet, and the other bed is 2.78 feet by 5.61 feet.

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Step-by-step explanation:

<h3> The complete exercise is attached.</h3><h3></h3>

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