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inn [45]
3 years ago
12

4. How do minerals become part of the soil?

Chemistry
2 answers:
Gelneren [198K]3 years ago
5 0
I think it is C hope it helps
Goryan [66]3 years ago
4 0

Answer:

Explain how nearly anyone could become a miner under Spanish Mining Code.

Explanation:

You might be interested in
What is the correct balanced equation for the following equilibrium constant expression?
weeeeeb [17]
The correct answer is 3) 2CO2(g) ⇄ 2CO(g)  + O2(g)

this is the correct one because it is a decomposition reaction and all the number of atoms is equal on both sides.

there are 2 C atoms on both sides. 

and 4 O atoms on both sides.

and 1) the atoms numbers are equal on both sides but not correct as it not a

correct number as it has 1/2 O2.


and 2) CO2(g) ⇆ CO(g) + O2 

the number of O atoms is not equal on both sides of the equation.

we have 2 O atoms on the left side and 3 O atoms on the right side.

so, this not a balanced equation.

4) also not correct 2CO(g) + O2 ⇆ 2CO2

as it is not a decomposition reaction and the 2CO & O2 are as reactants not products.

so the correct answer is 3) 2CO2(g) ⇆ 2CO(g) + O2(g)
8 0
3 years ago
How much volume would a 834.01g pile of sugar have given that it has a density of 1.59g/mL?
boyakko [2]

Answer:

v = 534.5mL

m = 597.15g

Density = 9.23g/mL

Density = 9.125g/mL

Explanation:

Density = mass/ volume

For the first question

Density = 1.59g/mL

Mass = 834.01g

Volume = ?

Using the above formula we have 1.59 = 834.01/v

v = 834.01/1.59

v = 534.5mL

For the second question

Density =0.9167g/mL

Volume = 651.41mL

Mass =?

Using the above formula we have

0.9167 =m/651.41

Cross multiply

m = 0.9167 x 651.41

m = 597.15g

For the third question

Mass =803.44g

Volume=87.03mL

Density =?

Density = 803.44/87.03

= 9.23g/mL

For the fourth

Density = 56.85/6.23

= 9.125g/mL

7 0
3 years ago
Calculate the mass of nitrogen dissolved at room temperature in an 95.0 LL home aquarium. Assume a total pressure of 1.0 atmatm
harina [27]

Answer:

86.3 g  of N₂ are in the room

Explanation:

First of all we need the pressure from the N₂ in order to apply the Ideal Gases Law and determine, the moles of gas that are contained in the room.

We apply the mole fraction:

Mole fraction N₂ = N₂ pressure / Total pressure

0.78 . 1 atm = 0.78 atm → N₂ pressure

Room temperature → 20°C → 20°C + 273 = 293K

Let's replace data: 0.78 atm . 95L = n . 0.082 . 293K

(0.78 atm . 95L) /0.082 . 293K = n

3.08 moles = n

Let's convert the moles to mass → 3.08 mol . 28g /1mol = 86.3 g  

8 0
2 years ago
Solutions are said to be what kind of mixture? A) Pure substance B) Heterogeneous C) Homogenous D) Element
laiz [17]
Solutions are said to be C. homogeneous mixtures, composed of two or more substances. It is usually liquid, however it may be solid or gas.
7 0
3 years ago
A certain gas occupies a volume of 26L when the applied pressure is 5.7atm. find the pressure in the system when the gas is comp
sergiy2304 [10]
P1 = 5.7atm V1 = 26L
P2 = ? V2 = 6.5 L

By Boyles Law,
P1V1 = P2V2
5.7 × 26 = P2 × 6.5
By solving,
P2 = 22.8atm.
8 0
3 years ago
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