Without consulting Appendix B, arrange each group in order of decreasing standard molar entropy (S°). Explain.(b) NO₂(g), NO(g),

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Without consulting Appendix B, arrange each group in order of decreasing standard molar entropy (S°). Explain.(b) NO₂(g), NO(g),

N₂(g)

Chemistry

1 answer:

denpristay [2] · Answer 1 · 2024-01-02T12:47:05+03:00

The decreasing order of standard molar entropy (S°) is as follow:

NO₂(g) > NO(g) > N₂(g)

<h3>What is Entropy? </h3>

Entropy is defined as the randomness of the particle. It depends on temperature and pressure or number of particle per unit volume.

It is directly proportional to the temperature and pressure of the gas.

<h3>What is Standard Molar Entropy? </h3>

The standard molar entropy is defined as the entropy content of the one mole of pure substance at the standard state of temperature and pressure of interest.

The standard molar entropy is also defined as the total amount of entropy which 1 mole of the substance acquire, as it is brought from 0K to standard conditions of temperature and pressure.

The standard molar entropy depends on the molas mass of atom, molecules or compound.

N₂ has lower standard molar entropy. This can be explained as this molecule consist of same atom.

While, Complexity increases from NO to NO₂(g). Therefore, the standard molar entropy of NO₂(g) is greater than NO.

Thus, we concluded that the decreasing order of standard molar entropy (S°) is as follow:

NO₂(g) > NO(g) > N₂(g)

learn more about standard molar entropy:

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