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lutik1710 [3]
3 years ago
12

Which is the most chemically active of all the elements?

Chemistry
2 answers:
liberstina [14]3 years ago
7 0
Answer
Fluorite
Explanation
Fluorine is a yellowish, poisonous, highly corrosive gas. It is the most chemically active nonmetallic element and is the most electronegative of all the elements. It is a member of Group 17 (the halogens ) of the periodic table .
SSSSS [86.1K]3 years ago
6 0

Answer:

its Fluorite

Explanation:

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5 0
2 years ago
Which of the following statements about salinity is true?
diamong [38]

Answer:

The answer would be B.

Explanation:

 

Ocean water near areas with low evaporation has higher salinity.

if im wrong please tell me .__.

4 0
3 years ago
Read 2 more answers
Give an example of change that includes more than one change​
bogdanovich [222]

Answer:

candle.

Explanation:

Candle has more than one change chemical and physical.

6 0
3 years ago
Additional solute is added to a saturated solution of a solid and a liquid after being heated above room temperature. Once no mo
PSYCHO15rus [73]

Answer:

After the solution is heated, but before additional solute is added

Explanation:

An unsaturated solution is a solution that contains less solute than it can normally hold at a given temperature. Hence an unsaturated solution can still dissolve more solute.

When the solution is heated, the saturated cold solution becomes an unsaturated hot solution which is capable of dissolving more solute at this point.

Once more solute is dissolved, the solution becomes saturated again just before it begins to cool since no more solute dissolves in the solution at some point before cooling and addition of seed crystals.

4 0
3 years ago
HELP ASAP PLZ!!!! Find the mass of each substance. Show your work.
Gemiola [76]

Answer:

A. m C5H12 = 108.23 g

B. m F2 = 547.142 g

C. m Ca(CN)2 = 71.85 g

Explanation:

  • mass (m) = mol (n) × molecular weigth (Mw)

∴ Mw C5H12 = ((12.011)(5)) + ((1.008)(12)) = 72.151 g/mol C5H12

∴ Mw F2 = (18.998)(2) = 37.996 g/mol F2

∴ Mw = Ca(CN)2 = 40.078+((12.011+14.007)(2)) = 92.114 g/mol Ca(CN)2

A. m C5H12 = ( 1.50 mol)×(72.151 g/mol) = 108.23 g C5H12

B. m F2 = (14.4 mol)×(37.996 g/mol) = 547.142 g F2

C. m Ca(CN)2 = (0.780 mol)×(92.114 g/mol) = 71.85 g Ca(CN)2

8 0
3 years ago
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