The function f(x) goes down by two and over by one:
slope = rise/run = -2/1 = -2.
The slope of f(x) is -2, while the slope of g(x) is -6.
Since -2 is a greater number than -6, the answer is:
C) <span>The slope of f(x) is greater than the slope of g(x). </span>
The answer is 6m djsjdjjsskskksksksksksksmsmsm
Step-by-step explanation:
Take the first derivative
![\frac{d}{dx} ( {x}^{3} - 3x)](https://tex.z-dn.net/?f=%20%5Cfrac%7Bd%7D%7Bdx%7D%20%28%20%7Bx%7D%5E%7B3%7D%20%20-%203x%29)
![3 {x}^{2} - 3](https://tex.z-dn.net/?f=3%20%7Bx%7D%5E%7B2%7D%20%20-%203)
Set the derivative equal to 0.
![3 {x}^{2} - 3 = 0](https://tex.z-dn.net/?f=3%20%7Bx%7D%5E%7B2%7D%20%20-%203%20%3D%200)
![3 {x}^{2} = 3](https://tex.z-dn.net/?f=3%20%7Bx%7D%5E%7B2%7D%20%20%3D%203)
![{x}^{2} = 1](https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20%20%3D%201)
![x = 1](https://tex.z-dn.net/?f=x%20%3D%201)
or
![x = - 1](https://tex.z-dn.net/?f=x%20%3D%20%20-%201)
For any number less than -1, the derivative function will have a Positve number thus a Positve slope for f(x).
For any number, between -1 and 1, the derivative slope will have a negative , thus a negative slope.
Since we are going to Positve to negative slope, we have a local max at x=-1
Plug in -1 for x into the original function
![( - 1) {}^{3} - 3( - 1) = 2](https://tex.z-dn.net/?f=%28%20-%201%29%20%7B%7D%5E%7B3%7D%20%20-%203%28%20%20-%201%29%20%3D%202%20)
So the local max is 2 and occurs at x=-1,
For any number greater than 1, we have a Positve number for the derivative function we have a Positve slope.
Since we are going to decreasing to increasing, we have minimum at x=1,
Plug in 1 for x into original function
![{1}^{3} - 3(1)](https://tex.z-dn.net/?f=%7B1%7D%5E%7B3%7D%20%20%20-%203%281%29)
![1 - 3 = - 2](https://tex.z-dn.net/?f=1%20-%203%20%3D%20%20-%202)
So the local min occurs at -2, at x=1
Answer:
29
Step-by-step explanation:
5^2 = 5x5
=25+4
=29
Answer:
The opposite of -11 is 11, and I dont understand what else you're asking
Step-by-step explanation: