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3 years ago

12

Use the figure to answer the questions

1 answer:

Stels [109]3 years ago

3 0

Answer:

A. EAB and EDC by AAA because congruent corresponding angles lead to similar triangles regardless of side length. This postulate works because the parallel lines cause angle a and angle d to be congruent as well as angle b being congruent to angle c, and vertical angle e is congruent.

Step-by-step explanation:

You might be interested in

Heather made a total of $451.78 last month at her part-time job. If she worked 14 hours, how much did she make per hour?

Step2247 [10]

The amount of money divided by the amount of hours will give you how much money she makes per hour.

451.78/14=32.27.

She earned $32.27 per hour.

3 0

3 years ago

–243 = -9(10 + w)<br><br> please help me

Verdich [7]

Answer:

w=17

Step-by-step explanation:

-243=-9(10+w)

-243=-90-9w

+90 +90

-153=-9w

17=w

hope this helps :)

8 0

2 years ago

Read 2 more answers

A rectangular container measuring 20 inches long by 16 inches wide by 12 inches tall is filled to its brim with water. If 850 cu

makkiz [27]

The new height of the water is = 9.34 inches (approx)

Step-by-step explanation:

Given, a rectangular container measuring 20 inches long by 16 inches wide by 12 inches tall is filled to its brim with water.

Let the new height of water level be x inches.

The volume of the container = (20×16×12) cubic inches

=3840 cubic inches

According to the problem,

3840 - (20×16×x) = 850

⇔3840 -320x = 850

⇔-320x =850-3840

⇔-320 x = -2990

$\Leftrightarrow x =\frac{2990}{320}$

⇔x = 9.34 inches

The new height of the water is = 9.34 inches (approx)

5 0

2 years ago

Alex drove 135 miles in 3 hours at a constant speed

Dominik [7]

Speed = distance / time
speed = 135/3 = 45 miles per hr <==

7 0

3 years ago

In triangle ΔABC, ∠C is a right angle and CD is the height to

Zina [86]

Answer:

$m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha$

Step-by-step explanation:

The triangles are drawn below.

CD is perpendicular to AB as CD is height to AB.

Therefore, angles $m\angle CDB=m\angle CDA=90$ °

So, triangles ΔCBD and ΔCAD are right angled triangles.

Now, from the right angled triangle ΔABC,

$m\angle A+m\angle B =90\\\alpha+m\angle B=90\\m\angle B=90-\alpha$

From ΔCBD,

$m\angle CBD$ is same as $m\angle B$ .

So, $m\angle CBD=90-\alpha$

$m\angle BCD+m\angle BDC =90\\m\angle BCD+90-\alpha=90\\m\angle BCD=\alpha$

Now, from ΔCAD,

$m\angle CAD$ is same as $m\angle A$

So, $m\angle CAD=\alpha$

$m\angle CAD+m\angle ACD =90\\\alpha+m\angle ACD=90\\m\angle ACD=90-\alpha$

Hence, the unknown angles of both the triangles are:

$m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha$

5 0

2 years ago