25.8%
First, determine how many standard deviations from the norm that 3 tons are. So:
(3 - 2.43) / 0.88 = 0.57/0.88 = 0.647727273
So 3 tons would be 0.647727273 deviations from the norm. Now using a standard normal table, lookup the value 0.65 (the table I'm using has z-values to only 2 decimal places, so I rounded the z-value I got from 0.647727273 to 0.65). The value I got is 0.24215. Now this value is the probability of getting a value between the mean and the z-score. What I want is the probability of getting that z-score and anything higher. So subtract the value from 0.5, so 0.5 - 0.24215 = 0.25785 = 25.785%
So the probability that more than 3 tons will be dumped in a week is 25.8%
Answer:
3
Step-by-step explanation:
Order of Operations; PEMDAS
Parentheses
Exponents
Multiplication & Division (Left to Right) (ex: 10x2÷5) You would do whatever comes left for Multiplication or Division.
Addition & Subtraction (Left to Right) (ex: 10-2+5) You would do whatever comes left for Addition & Subtraction.
3x+6 =
(9+6=15)
(6x2=12)
(12-15=<u>3</u>)
3*4 + 1*5 / 5*4=
12+5/20=
17/20
Solutions
We know that <span>the mass of a tiger at a zoo is 235 kilograms. Randy's cat has a mass of 5,000 grams. To solve the problem we have to convert 235 kilograms into grams.
</span>235 kilograms = 235000 grams
<span>Randy's cat has a mass of 5,000 grams
</span>
Randy's cat = <span>5,000 grams
</span>
Tiger = <span>235000 grams
</span>
Our next step is to subtract 5000 from <span>235000 grams
</span>
235000 grams - <span>5000 grams = 230000
</span>
Answer = <span>230000 grams </span>
Answer:
A x, y
Step-by-step explanation:
Hopefully this helps
