Answer:
E) we will use t- distribution because is un-known,n<30
the confidence interval is (0.0338,0.0392)
Step-by-step explanation:
<u>Step:-1</u>
Given sample size is n = 23<30 mortgage institutions
The mean interest rate 'x' = 0.0365
The standard deviation 'S' = 0.0046
the degree of freedom = n-1 = 23-1=22
99% of confidence intervals 
(from tabulated value).
using calculator
Confidence interval is
the mean value is lies between in this confidence interval
(0.0338,0.0392).
<u>Answer:-</u>
<u>using t- distribution because is unknown,n<30,and the interest rates are not normally distributed.</u>
Answer:
5 hours
Step-by-step explanation:
31-11 = 20
20/4 = 5
(2x^2 + 16x + 30) / (5x^2 + 13x -6)
Start by factoring the numerator and denominator.
Cancel any like factors.
2(x^2 + 8x + 15)
2(x + 5)(x + 3) / (5x -2)(x + 3
2(x + 5) / (5x - 2)
The third choice
Call Anita's score
and Joelle's score
.
1) "<span>their combined total score for one game was 425 points"
</span>Therefore
2)"Anita’s score was 40 less than twice Joelle’s."
Therefore
Substitute:
Solve:
Backsubstitute:
8r(40)=4
r=1/80 that is the rate for each person...
10rt=7 using r we found before
10(1/80)t=7
t/8=7
t=56 minutes.
