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IRINA_888 [86]
3 years ago
6

What name is applied to sound vibrations above audio range?​

Physics
1 answer:
asambeis [7]3 years ago
4 0
Audio frequency

An audio frequency or audible frequency is a periodic vibration whose frequency is in the band audible to the average human, the human hearing range.
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The Achilles tendon connects the muscles in your calf to the back of your foot. When you are sprinting, your Achilles tendon alt
Andrews [41]

Explanation:

It is given that,

Mass of the runner, m = 70 kg

Length of the tendon, l = 15 cm = 0.15 m

Area of cross section, A=110\ mm^2=0.00011\ m^2

Part A,

Let the runner's Achilles tendon stretch if the force on it is 8.0 times his weight, F = 8 mg

Young's modulus for tendon is, Y=0.15\times 10^{10}\ N/m^2

The formula of the Young modulus is given by :

Y=\dfrac{F/A}{\dfrac{\Delta L}{L}}

0.15\times 10^{10}=\dfrac{8\times 70\times 9.8/0.00011}{\dfrac{\Delta L}{0.15}}

\Delta L=0.0049\ m

Part B,

The fraction of the tendon's length does this correspond is given by :

\dfrac{\Delta L}{L}=\dfrac{0.0049}{0.15}

\dfrac{\Delta L}{L}=0.0326

Hence, this is the required solution.

6 0
3 years ago
How is the world do you do this?
Rainbow [258]
You do the net force by subtracting the sides. The direction of the box is moving forward to the right by 10 N.
4 0
3 years ago
In 1976, the SR-71A, flying at 20 km altitude (T = –56 0C), set the official jet-powered aircraft speed record of 3530 km/hr (21
Lapatulllka [165]

To solve this problem we will apply the concepts related to the calculation of the speed of sound, the calculation of the Mach number and finally the calculation of the temperature at the front stagnation point. We will calculate the speed in international units as well as the temperature. With these values we will calculate the speed of the sound and the number of Mach. Finally we will calculate the temperature at the front stagnation point.

The altitude is,

z = 20km

And the velocity can be written as,

V = 3530km/h (\frac{1000m}{1km})(\frac{1h}{3600s})

V = 980.55m/s

From the properties of standard atmosphere at altitude z = 20km temperature is

T = 216.66K

k = 1.4

R = 287 J/kg

Velocity of sound at this altitude is

a = \sqrt{kRT}

a = \sqrt{(1.4)(287)(216.66)}

a = 295.049m/s

Then the Mach number

Ma = \frac{V}{a}

Ma = \frac{980.55}{296.049}

Ma = 3.312

So front stagnation temperature

T_0 = T(1+\frac{k-1}{2}Ma^2)

T_0 = (216.66)(1+\frac{1.4-1}{2}*3.312^2)

T_0 = 689.87K

Therefore the temperature at its front stagnation point is 689.87K

6 0
4 years ago
Please help and if you get this and answer the other one on my thing i’ll give u brainliest
quester [9]

Answer:

The higher the energy, the shorter the wavelength.

Explanation:

3 0
3 years ago
A 2N and 6N force pull on an object to the right and a 4N force pulls to the left a 0.5kg object. What is the net force on the o
Angelina_Jolie [31]

Explanation:

F net = 2+6-4 ( 2 and 6 N are in same direction so they get added, 4N in opposite direction so it will be subtracted)

F net=4 N

3 0
3 years ago
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