All categories

3 years ago

An object with a mass of 2.0 kg is accelerated at 5.0 m/s/s. the net force acting on the mass is

2 answers:

7 0

First we need to know the equation:
F= Mass times acceleration
F = 2.0 kg times 5.0 m/s^2
multiply them to get the net force!
F= 10 N
N is newton
Hope this heps

Arlecino [84]3 years ago

3 0

Answer:

Fn = 10 N

Explanation:

Newton's second law:

∑F = m*a Formula (1)

∑F : Net force acting on the mass or algebraic sum of the forces in Newton (N)

m : mass s (kg)

a : acceleration (m/s²)

Data

m = 2.0 kg : mass of the object

a = 5.0 m/s² : acceleration of the object

Calculation of the net force (Fn) acting on the mass

We apply the formula (1)

∑F = m*a, ∑F = Fn

Fn = m*a

Fn = (2.0 kg)* (5.0 m/s²)

Fn = 10 N

You might be interested in

Which two processes increase the motion of the molecules?

anzhelika [568]

The answer is 2 because a and b are slowing it down by condensing it and then freezing it so its not one, b and c are opposites because b slows it down whereas c speeds it up so its not 3, and number 4 is the same explanation for number 3
hope you pass :)

5 0

3 years ago

A student drops a rock from a bridge to the water 12.7 m below. with what speed does the rock strike the water? the acceleration

kolezko [41]

The rock strike the water with the speed of 15.78 m/sec.

The speed by which rock hit the water is calculated by the formula

v= $\sqrt{2gh}$

v= $\sqrt{2*9.8*12.7}$

v=15.78 m/sec

Hence, the rock strike the water with the speed of 15.78 m/sec.

7 0

2 years ago

A 100 kg box is suspended from two ropes. The "left rope makes an angle of 20" degrees with the vertical, and the right rope mak

GarryVolchara [31]

Explanation:

It is given that,

Mass of the box, m = 100 kg

Left rope makes an angle of 20 degrees with the vertical, and the right rope makes an angle of 40 degrees.

From the attached figure, the x and y component of forces is given by :

$T_{1x} =-T_1 cos (20)$

$T_{2x} = T_2 cos (40)$

$mg_x = 0$

$T_{1y} = T_1 sin (20)$

$T_{2y} = T_2 sin (40)$

$mg_y= -mg$

Let $R_x$ and $R_y$ is the resultant in x and y direction.

$R_x=-T_1 cos (20)+T_2 cos (40)+0$

$R_y=T_1 sin(20)+T_2 sin(40)-mg$

As the system is balanced the net force acting on it is 0. So,

$-T_1 cos (20)+T_2 cos (40)+0=0$ .............(1)

$T_1 sin(20)+T_2 sin(40)-100\times 9.8=0$ ..................(2)

On solving equation (1) and (2) we get:

$T_1=866.86\ N$ (tension on the left rope)

$T_2=1063.36\ N$ (tension on the right rope)

So, the tension on the right rope is 1063.36 N. Hence, this is the required solution.

7 0

3 years ago

Parents have a major role in observing how young children grow at home. Create and discuss simple developmental monitoring tips

Rudik [331]

Answer:

by observation of their children

4 0

2 years ago

Describe how substance move from one state to another

Mekhanik [1.2K]

The temperature rises until the water reaches the next change of state — boiling. As the particles move faster and faster, they begin to break the attractive forces between each otherand move freely as steam — a gas. The process by which a substance moves from the liquid state to the gaseousstate is called boiling.

4 0

3 years ago

Read 2 more answers