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nordsb [41]
3 years ago
12

The sum of the two decimals is 1 the product of these decimals is 0.25 the quotient of these two decimals is 1 what are the two

fractions
Mathematics
1 answer:
ExtremeBDS [4]3 years ago
5 0
Since the quotient of the two decimal numbers is 1, that tells use that they are the same number.
Since the sum of the two numbers equals 1 and both numbers are the same, then the answer must be 1 divided by 2. or .5
the fractions would be 1/2 and 1/2

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Estimate the Value Of Each Expression to the nearest integer .
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Answer:

see below

Step-by-step explanation:

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15. Again, 3 is √9 and 4 is √16. 9 < 10 < 16 so √10 is in between 3 and 4, however, since 10 is closer to 9 as it is to 16, we know that √10 is about 3.

16. -4 = -√16 and -5 = -√25, since 16 < 22 < 25, we know that -√22 is in between -4 and -5 but 22 is closer to 25 so the answer is -5.

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3 years ago
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Lelu [443]

Answer:

A≈576.31

Step-by-step explanation:

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8 0
2 years ago
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Taya2010 [7]
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7 0
3 years ago
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A research group needs to determine a 90% confidence interval for the mean repair cost for all car insurance small claims. From
lutik1710 [3]

Answer:

a) z = 1.645

b) The should sample at least 293 small claims.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645, which means that the answer of question a is z = 1.645.

Now, find  the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

(b) If the group wants their estimate to have a maximum error of $12, how many small claims should they sample?

They should sample at least n small claims, in which n is found when

M = 12, \sigma = 124.88. So

M = z*\frac{\sigma}{\sqrt{n}}

12 = 1.645*\frac{124.88}{\sqrt{n}}

12\sqrt{n} = 205.43

\sqrt{n} = \frac{205.43}{12}

\sqrt{n} = 17.12

\sqrt{n}^{2} = (17.12)^{2}

n = 293

The should sample at least 293 small claims.

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3 years ago
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BCD and BAD is correct
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2 years ago
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