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alekssr [168]
2 years ago
12

Explain why all squares must be rectangles but not all rectangles are squares

Mathematics
1 answer:
Neko [114]2 years ago
5 0
A square is a quadrilateral with all four angles right angles and all four sides of the same length. ... Thus every square is a rectangle because it is a quadrilateral with all four angles right angles. However not every rectangle is a square, to be a square its sides must have the same length.
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A tire company produced a batch of 6 comma 700 tires that includes exactly 250 that are defective.
mezya [45]

the probability that if you pick only one, it's defective, is 250/6700

Therefore, the probability that one is not defective is 6450/6700

a. You want all 4 to not be defective: (6450/6700)^4

b. all 100 have to be not defective: (6450/6700)^100

If you type this into a calculator, you will get about 0.022, so a probability of 2 % that all of them are not defective. As this is a very small probability, the outlet should plan with returned tires.

8 0
3 years ago
Please help me do this i’ll give brainlist and points
lorasvet [3.4K]

To make enough brew for 4 people you would need:

3 frogs

4 1/2 cups of sour milk

14 gerbil tails

52 crickets

2/3 cup of eyeballs

2 Twinkies

<em>Have a luvely day!</em>

3 0
2 years ago
We learned in that about 69.7% of 18-20 year olds consumed alcoholic beverages in 2008. We now consider a random sample of fifty
maw [93]

Answer:

(1) The expected number of people who would have consumed alcoholic beverages is 34.9.

(2) The standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3) It is surprising that there were 45 or more people who have consumed alcoholic beverages.

Step-by-step explanation:

Let <em>X</em> = number of adults between 18 to 20 years consumed alcoholic beverages in 2008.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.697.

A random sample of <em>n</em> = 50 adults in the age group 18 - 20 years is selected.

An adult, in the age group 18 - 20 years, consuming alcohol is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 50 and <em>p</em> = 0.697.

The probability mass function of a Binomial random variable <em>X</em> is:

P(X=x)={50\choose x}0.697^{x}(1-0.697)^{50-x};\ x=0,1,2,3...

(1)

Compute the expected value of <em>X</em> as follows:

E(X)=np\\=50\times 0.697\\=34.85\\\approx34.9

Thus, the expected number of people who would have consumed alcoholic beverages is 34.9.

(2)

Compute the standard deviation of <em>X</em> as follows:

SD(X)=\sqrt{np(1-p)}=\sqrt{50\times 0.697\times (1-0.697)}=10.55955\approx10.56

Thus, the standard deviation of people who would have consumed alcoholic beverages is 10.56.

(3)

Compute the probability of <em>X</em> ≥ 45 as follows:

P (<em>X</em> ≥ 45) = P (X = 45) + P (X = 46) + ... + P (X = 50)

                =\sum\limits^{50}_{x=45} {50\choose x}0.697^{x}(1-0.697)^{50-x}\\=0.0005+0.0001+0.00002+0.000003+0+0\\=0.000623\\\approx0.0006

The probability that 45 or more have consumed alcoholic beverages is 0.0006.

An unusual or surprising event is an event that has a very low probability of success, i.e. <em>p</em> < 0.05.

The probability of 45 or more have consumed alcoholic beverages is 0.0006. This probability value is very small.

Thus, it is surprising that there were 45 or more people who have consumed alcoholic beverages.

6 0
2 years ago
1. Write the equation for a line in point slope form that had a slope of 4 and passes through (1,1)
Dahasolnce [82]

Solution:

<u>Note that:</u>

  • Slope = m = 4
  • Given point: (x₁,y₁) = (1,1) [x₁ = 1; y₁ = 1]
  • Formula: y - y₁ = m(x - x₁)

<u>Use the formula to convert the line in point slope form.</u>

  • y - y₁ = m(x - x₁)
  • y - 1 = 4(x - 1)

The equation of the line (In point slope form) is y - 1 = 4(x - 1).

8 0
2 years ago
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Select the correct answer. Rectangle ABCD is dilated by a scale factor of 2 with the origin as the center of dilation, resulting
Natalija [7]
So I have a illustration
4 0
3 years ago
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