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MAXImum [283]
3 years ago
15

An ant is walking at a speed of 42 centimeters in 5 minutes. what rate did the ant walk

Mathematics
1 answer:
Keith_Richards [23]3 years ago
7 0

divide 42 cm. by 5 minutes, which leaves you with 8.4 cm/minute. hope this helps, please mark brainliest and have a great day

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A cyclist rides at a constant speed of 15 miles per hour. At this speed, about how long would it take the cyclist to ride from F
frozen [14]

We need to find the time taken to travel from Frederick, MD to Baltimore, MD at a speed of 15 miles per hour.

The time taken to travel the distance is 3 hours and 20 minutes.

The shortest route from Frederick to Baltimore is 50.2 miles via the I-70 E.

So we can assume this route will be taken.

Speed of the cyclist = 15 mph

Time is given by distance divided by speed.

So,

t=\dfrac{50.2}{15}\\\Rightarrow t=3.34\ \text{hours}

Converting to hours and minutes

0.34\times 60=20.4\approx 20

The time taken by the cyclist would be about 3 hours and 20 minutes.

Learn more:

brainly.com/question/6716662

brainly.com/question/16869288

4 0
3 years ago
Adding negative and positive numbers.
vichka [17]
When you add 2 negatives you get a negative for example -5+-15= -20 when you add a positive to a negative it increases the number for example -20+7= -13. Hope this helps 
7 0
3 years ago
Read 2 more answers
Samira ran around a park loop that was one-third mile long. she ran around the loop nine times. samira says she ran 9/3 miles. h
Alexeev081 [22]
1/3 mile x 9 times = 3

They both are 9/3 simplifies to 3
4 0
3 years ago
how would you convert the repeating, nonterminating decimal to a fraction? explain the process as u solve the problem 0.1515...
deff fn [24]
.1515/1  1.515/10 15.15/100 151.5/1000  1515/10000

multiply the numerator and the denominator by 10

your answer is 1515/10000

simplified is 303/2000
4 0
3 years ago
Suppose that 3\%3%3, percent of over 200{,}000200,000200, comma, 000 books borrowed from a library in a year are downloaded. The
sleet_krkn [62]

Answer:

The mean of the sampling distribution of the proportion of downloaded books is 0.03 and the standard deviation is 0.0197.

Step-by-step explanation:

Central Limit Theorem

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean \mu = p and standard deviation s = \sqrt{\frac{p(1-p)}{n}}

3% of books borrowed from a library in a year are downloaded.

This means that p = 0.03

SRS of 75 books.

This means that n = 75

What are the mean and standard deviation of the sampling distribution of the proportion of downloaded books

By the Central Limit Theorem

Mean: \mu = p = 0.03

Standard deviation: s = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.03*0.97}{75}} = 0.0197

The mean of the sampling distribution of the proportion of downloaded books is 0.03 and the standard deviation is 0.0197.

4 0
3 years ago
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