Please hurry and hurry up on my other question
2 answers:
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The trick here is to substitute points given
substituting point A x-value =b
turns out false since (b,a*b^b) !=(b,0)
substituting point B x-value=0
turns out true since (0,a)=(0,a)
we already got f(x) at x =0 which is not the point (0,0)
so c is false
substituting D x-value=a
hence B is the correct answers
substituting point A x-value =b
turns out false since (b,a*b^b) !=(b,0)
substituting point B x-value=0
turns out true since (0,a)=(0,a)
we already got f(x) at x =0 which is not the point (0,0)
so c is false
substituting D x-value=a
hence B is the correct answers