A sequence of numbers is formed by the iterative process Xn+1 = (Xn )2 – Xn
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The function F(x) have a vertical asymptote at x =0 and x =1.
Given that
The given Function;
We have to determine
At which value the function F(x) has a vertical asymptote.
According to the question
The given Function;
The function is undefined when the denominator becomes 0. Find values of x for which the denominator is 0:
Then,
The value of x is 0 and 1.
Hence, the function F(x) have a vertical asymptote at x =0 and x =1.
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