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2 years ago

An animal shelter has three kinds of Labrador Retrievers: yellow, brown, and black. They have

Mathematics

1 answer:

barxatty [35]2 years ago

6 0

Step-by-step explanation:

There are choices when it comes to color (3). Then there is the choice between a boy dog or a girl dog (2). Multiply the number of colors by the number of genders. (6)

When choosing a dog from random, you can either choose:

Brown/M

Brown/F

Black/M

Black/F

Yellow/M

Yellow/F

(This list is called the Sample Space, a list of all possible outcomes)

Because the text says that all types of dogs are found in even numbers, it would not matter if there was 6, 12, 18, ... amount of dogs.

When looking at this sample space, you can see that the chance of choosing a Yellow/F dog, is 1 in 6.

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2 years ago

Is -2 a solution to 4x^(3)-x^(2)+16x-4

sergiy2304 [10]

Answer:

Not a solution

Step-by-step explanation:

In order for $x=-2$ to be a solution, the result after substituting must be 0:

$4(-2)^3-(-2)^2+16(-2)-4\stackrel{?}{=}0$

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3 0

2 years ago

Which values of a and b make the following equation true? a = 11, b = 7 a = 11, b = 10 a = 28, b = 7 a = 28, b = 10

xz_007 [3.2K]

Answer:

The answer is

Step-by-step explanation:

$( {5x}^{7} {y}^{2} )( { - 4x}^{4} {y}^{5} ) = - 20 {x}^{a} {y}^{b}$

Multiply the terms on the left side of the equation

That's

$- 20 {x}^{11} {y}^{7} = - 20 {x}^{a} {y}^{b}$

Since the bases are the same we can equate the exponents

That's

${x}^{11} = {x}^{a}$

a = 11

And

${y}^{7} = {y}^{b}$

b = 11

Therefore

a = 11 and b = 7

Hope this helps you

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3 years ago