3 years ago

400+90+7,000+ blank =7,495

Mathematics

1 answer:

Feliz [49]3 years ago

8 0

Answer:

The answer is for this question is 5.

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The value, V (t), in dollars, of a stock t months after it is purchased is modeled by the following equation.

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Answer:

Step-by-step explanation: $V(t)= 42(1-e ^{1.5t} ) +36$ is given value in dollars of a stock in t months after it is purchased.

a) Substitute 1 for t

$V(1) = 42(1-e^{-1.5} )+36 \\=67.852\\=67.85$

V(12) = $V(1) = 42(1-e^{-1.5*12} )+36 \\=77.00$

b) Find derivative for V

$V'(t) = 42(-1.5) e^{-1.5t} )\\\\=-63e^{-1.5t}$

c) When V(t) = 75

$V(t)=75= 42(1-e ^{1.5t} ) +36\\1-e ^{1.5t=0.9286\\=-2.639$

d) As t tends to infinity, exponent being in negative t tends to 0

So V tends to 42(1-0)+36 = 78

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3 years ago

True or false:<br> The solution, root, x-intercept, and zero of a problem are the same.

cluponka [151]

This is true . Solution , root , x and zero all are the same thing

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2 years ago

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Determine the slope of the line. Please explain the answer . If you hurry I’ll mark brainliest

Daniel [21]

Answer:

2/4

Step-by-step explanation:

Rise over run. you go up 2 and right 4

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Newton’s law of cooling states that the temperature of an object changes at a rate proportionalto the difference between the tem

Verizon [17]

Answer:

$\frac{dT}{dt} = -0.05\;min^{-1} (T-70\ºF)$

Step-by-step explanation:

Hi!

Lets call:

T = temprature of the object

T₀ = temperature of surroundings

t = time

The rate of change of T is its derivative with respecto to time. If T > T₀, the object looses heat, so T decreases. Then, being k > 0:

$\frac{dT}{dt} = -k(T-T_0) \\$

In this case T₀ = 70ºF and k = 0.05/min. Then the differential equation is:

$\frac{dT}{dt} = -0.05\;min^{-1} (T-70\ºF)$

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3 years ago

Please answer asap...

ehidna [41]

Answer:

The answer is C pay attention in class next time

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3 years ago