The depreciated value in year 4 is 14,000. In year 5, it is 8,400. The depreciation expense in year 5 is
.. $14,000 -8,400 = $5,600
<h2>
Answer: g(f(2)) = 11</h2>
Step-by-step explanation:
g(f(2)) is substituting the value of f(2) for x in g(x). But we must first find f(2).
We know that f (x) = ax² - 12
Since f(3) = 24
⇒ a(3²) - 12 = 24
9 a = 36
a = 4
∴ f(2) = (4)(2²) - 12
= 4
⇒ g(f(2)) = 2(4) + 3
= 11
The answer for the given above is letter "a, -6r2s4t3". This is obtained by dividing 18 by -3 and subtracting the exponent below with that from above of the same variable. For r, subtract 2 from 4 to get 2. For s, subtract 1 from 5 to get 4 and lastly for t, subtract 3 from 6 to get 3.
Answer:
80
Step-by-step explanation:
Answer:

Step-by-step explanation:
Given
Geometry Progression


Required
Calculate the second term
First, we need to write out the formula to calculate the nth term of a GP

For first term: Tn = 500 and n = 1




For fought term: Tn = 32 and n = 4


Substitute 500 for a

Make r^3 the subject


Take cube roots
![\sqrt[3]{r^3} = \sqrt[3]{0.064}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Br%5E3%7D%20%3D%20%5Csqrt%5B3%5D%7B0.064%7D)
![r = \sqrt[3]{0.064}](https://tex.z-dn.net/?f=r%20%20%3D%20%5Csqrt%5B3%5D%7B0.064%7D)

Using: 
and 




<em>Hence, the second term is 200</em>