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4 years ago

Factor the polynomial by it’s greatest common monomial factor. 12k^3 - 30k^4

Mathematics

2 answers:

Lemur [1.5K]4 years ago

7 0

Answer:

$6k^3(2-5k)$

Step-by-step explanation:

Find the GCF, 6.

Factor out $6k^3$ :

$12k^3-30k^4\\6k^3(2-5k)$

Finito.

madam [21]4 years ago

5 0

Answer:

6k^3(2 - 5k)

Step-by-step explanation:

12k^3 - 30k^4

Factor out 6k^3

6k^3(2 - 5k)

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If EF=9x+14, FG=56, and EG=250, find the value of x.

nexus9112 [7]

Answer:

Value of x =20

Step-by-step explanation:

Given: EF = 9x+14 units , FG = 56 units and EG = 250 units.

Segment Addition Postulates states the following for 3 points that are collinear.

i.e, Let three points A, B and C are collinear and B is between A and C.

i,e AC = AB + BC

By Segment addition postulates; solve for x;

EG = EF + FG

Substitute the given values we get;

250 = 9x + 14 + 56

250 = 9x + 70

Subtract 70 on both sides we get;

250 -70 = 9x + 70 -70

Simplify:

180 = 9x

Divide both sides by 9 we get;

$\frac{180}{9} = \frac{9x}{9}$

Simplify:

x = 20

Therefore, the value of x =20

7 0

4 years ago

Read 2 more answers

The square of nine less than a number is three less than the number. What is the number ?

kvv77 [185]

Let n represent the number.
.. (n -9)^2 = n -3 . . . . . the square of 9 less than the number is 3 less than the number
.. n^2 -18n +81 = n -3
.. n^2 -19n +84 = 0
.. (n -7)(n -12) = 0
.. n = 7 or 12

The number could be 7 or 12.

_____
Check:
.. (7 -9)^2 = (-2)^2 = 4 = 7 -3 . . . . answer checks OK
.. (12 -9)^2 = 3^2 = 9 = 12 -3 . . . . answer checks OK

3 0

3 years ago

Please HELP For the function,f(x)=-2x^2, find f(-3)

Amanda [17]

Answer:

-18

Step-by-step explanation:

F(x)=-2x^2

f(-3) means substitute x with -3

= -2(-3)^2

= -18

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3 0

4 years ago

Partition the line below

Alik [6]

Answer:

it would be the second fifth

Step-by-step explanation:

There are two of them so it would be the second one.

4 0

3 years ago

NEED HELP In 5 OR MORE SENTENCES, write a short story explaining the graph OR write about the key features of the graph.

posledela

A short story that explains the graph is a man riding a sport car.

He spent a total time of 60 s.
He initial distance covered (50 m) at a speed of 2 m/s (rate of change in section A) before making a stop (section B).
He then covered another distance (30 m) at a speed of 3 m/s (rate of change in section C) before finally stopping.
In a total of 60 s, he traveled a total distance of 80 m.

A short story that can be written for the graph is a story of a man riding a sport car. He made a stop then continued later.

Section A shows the time spent and distance traveled from his the start position to when he stopped at first.

Section B shows the time spent when he first stopped.

Section C shows the time and distance traveled before arriving at his final destination.

The following are some details and key features of the graph:

1. The rate of change in each section:

Section A rate of change = rise/run $= \frac{50 - 0}{25 - 0} = \frac{50}{25} = 2 $ m/s$

Section B rate of change = rise/run $=\frac{50 - 50}{60 - 25} = \frac{0}{35} = 0 $ m/s$

Section C rate of change = rise/run $=\frac{80 - 50}{70 - 60} = \frac{30}{10} = 3 $ m/s$

The rate of change here represents the speed at which he drove.

2. The distance traveled in each section:

Distance traveled in Section A = 50 - 0 = 50 m

Distance traveled in Section B = 50 - 50 = 0 m

Distance traveled in Section C = 80 - 50 = 30 m

3. The total distance traveled:

Total distance = 50 + 0 + 30 = 80 m

4. The total time spent traveling:

Total time spent = 70 - 0 = 60 s

In summary, a short story that explains the graph is a man riding a sport car.

He spent a total time of 60 s.
He initial distance covered (50 m) at a speed of 2 m/s (rate of change in section A) before making a stop (section B).
He then covered another distance (30 m) at a speed of 3 m/s (rate of change in section C) before finally stopping.
In a total of 60 s, he traveled a total distance of 80 m.

Learn more here:

brainly.com/question/24654519

4 0

3 years ago