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bogdanovich [222]

3 years ago

12

I need help finding

20%7D%20" id="TexFormula1" title=" \frac{ {3}^{9} }{ {3}^{ - 5} } " alt=" \frac{ {3}^{9} }{ {3}^{ - 5} } " align="absmiddle" class="latex-formula">

1 answer:

Sunny_sXe [5.5K]3 years ago

4 0

Answer:

4782969

Step-by-step explanation:

Reduce the expression, if possible, by cancelling the common factors.

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If x3= 27 and y3 =125, what is the value of y-x

Leno4ka [110]

Answer:

32 2/3

(32.6 repeating)

Step-by-step explanation:

29/3 is 9 (just make it not 3 Xs,) so x=9

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Please help me ASAP!Please this is due soon and i don't have all day.

Helga [31]

<u><em>Answer:</em></u>

Section 1: 5.59%

Section 2: -2.16%

Section 3: -10.82%

Section 4: -6.54%

Section 5: -2.16%

Section 6: 7.86%

<u><em>Explanation:</em></u>

<u>The formula to calculate the percent change in mass is given as:</u>

$PercentChange = \frac{ChangeInMass}{StartingMass}*100=\frac{NewMass - OldMass}{OldMass}*100$

<u>1- Section 1:</u>

Old mass = 7.83 g and New mass = 8.268 g

$PercentChange = \frac{8.268-7.83}{7.83}*100 =$ 5.59%

<u>2- Section 2:</u>

Old mass = 7.4 g and New mass = 7.24 g

$PercentChange = \frac{7.24-7.4}{7.4}*100 =$ -2.16%

<u>3- Section 3:</u>

Old mass = 7.3 g and New mass = 6.51 g

$PercentChange = \frac{6.51-7.3}{7.3}*100 =$ -10.82%

<u>4- Section 4:</u>

Old mass = 7.49 g and New mass = 7.0 g

$PercentChange = \frac{7.0-7.49}{7.49}*100 =$ -6.54%

<u>5- Section 5:</u>

Old mass = 7.4 g and New mass = 7.24 g

$PercentChange = \frac{7.24-7.4}{7.7.4}*100 =$ -2.16%

<u>6- Section 6:</u>

Old mass = 7.89 g and New mass = 8.51 g

$PercentChange = \frac{8.51-7.89}{7.89}*100 =$ 7.86%

Hope this helps :)

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Step-by-step explanation:

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