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3 years ago

Im just looking for 25/4 (that's a fraction) divided in 3.

Mathematics

2 answers:

Hatshy [7]3 years ago

8 0

Answer:

$\frac{25}{12}$

Step-by-step explanation:

1) Use this rule: a ÷ b/c = a × c/b.

$\frac{25}{4} \times \frac{1}{3}$

2) Use this rule: a/b × c/d = ac/bd.

$\frac{25 \times 1}{4 \times 3}$

3) Simplify 25 × 1 to 25.

$\frac{25}{3 \times 4}$

4) Simplify 3 × 4 to 12.

$\frac{25}{12}$

Therefor, the answer is 25/12 and in decimal form it would be, 2.083333.

ANTONII [103]3 years ago

5 0

Answer: 2.083
Have a good day :D

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If the measures of two angles of a triangle are 87 and 17 , what is the measure of the third angle

Serhud [2]

Answer:

76 degrees

Step-by-step explanation:

The total of the three angles in a triangle should equal 180 degrees. So to find the third angle, subtract the two given angles from 180

180 - 87 = 93

93 - 17 = 76

The third angle is 76 degrees because then all angles will add up to 180

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3 years ago

The graphs of f(x)=−53x+9 and g(x)=2x−1 intersect at (3,4) .

aleksandr82 [10.1K]

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3 years ago

Read 2 more answers

Find constants a and b such that the function y = a sin(x) + b cos(x) satisfies the differential equation y'' + y' − 5y = sin(x)

vichka [17]

Answers:

a = -6/37

b = -1/37

============================================================

Explanation:

Let's start things off by computing the derivatives we'll need

$y = a\sin(x) + b\cos(x)\\\\y' = a\cos(x) - b\sin(x)\\\\y'' = -a\sin(x) - b\cos(x)\\\\$

Apply substitution to get

$y'' + y' - 5y = \sin(x)\\\\\left(-a\sin(x) - b\cos(x)\right) + \left(a\cos(x) - b\sin(x)\right) - 5\left(a\sin(x) + b\cos(x)\right) = \sin(x)\\\\-a\sin(x) - b\cos(x) + a\cos(x) - b\sin(x) - 5a\sin(x) - 5b\cos(x) = \sin(x)\\\\\left(-a\sin(x) - b\sin(x) - 5a\sin(x)\right) + \left(- b\cos(x) + a\cos(x) - 5b\cos(x)\right) = \sin(x)\\\\\left(-a - b - 5a\right)\sin(x) + \left(- b + a - 5b\right)\cos(x) = \sin(x)\\\\\left(-6a - b\right)\sin(x) + \left(a - 6b\right)\cos(x) = \sin(x)\\\\$

I've factored things in such a way that we have something in the form Msin(x) + Ncos(x), where M and N are coefficients based on the constants a,b.

The right hand side is simply sin(x). So we want that cos(x) term to go away. To do so, we need the coefficient (a-6b) in front of that cosine to be zero

a-6b = 0

a = 6b

At the same time, we want the (-6a-b)sin(x) term to have its coefficient be 1. That way we simplify the left hand side to sin(x)

-6a -b = 1

-6(6b) - b = 1 .... plug in a = 6b

-36b - b = 1

-37b = 1

b = -1/37

Use this to find 'a'

a = 6b

a = 6(-1/37)

a = -6/37

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2 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

The per capita consumption of red meat by people in a country in a recent year was normally distributed, with a mean of 107107

Pachacha [2.7K]

Answer:

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Step-by-step explanation:

Given data

mean = 107 pounds

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no of sample (n) = 18

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sample means

solution

according to question we know mean of sample = 107 pounds

so standard error of this sample will be standard deviation / $\sqrt{n}$

now put all value n and standard deviation and we get sample mean i.e.

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