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Tomtit [17]
3 years ago
9

Can race condition happen in monolithic memcached. a. True b. False

Computers and Technology
1 answer:
erica [24]3 years ago
8 0

Answer:

True

Explanation:

It is TRUE that race condition happens in monolithic Memcached. This is evident in that in a python language, where Memcached "gets" and "set" function tends to turn to a race condition if for example the two functions are used together to accomplish similar things like locking given that it is not atomic.

Hence, in this case, the correct answer is TRUE

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Suppose the inventory is unordered (!) and a sequential search is done to locate a specific artifact. Given that the search is e
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Answer:

The computer can do 12000 searches per second. Suppose there are 60000 inventory items. And we need to search one item from it in a sequential manner. The computer can do 12000 searches in one second. Hence it can search in a list of 60000 inventory in 5 seconds, as 12000 x 5 =60000 searches, in the worst case. And if the item is below 12000 on the list, it will take less than 1 second(1/12000 sec in best case), and so on.

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Explanation:

Please check the answer section.

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Polygon transform (25 points). Write a library of static methods that performs various geometric transforms on polygons. Mathema
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Answer:

import java.lang.*;               //for using Math.cos() and Math.sin() and Math.toRadians() funcitons in rotate method

public class PolygonTransform

{

  public static double[] copy(double[] array)

  {

      double[] newArray = new double[array.length];

      for(int i=0;i<array.length;i++)

      {

          newArray[i] = array[i];

          return newArray;

      }

  }

  public static void scale(double[]x,double[]y,double alpha)

  {

      for(int i=0;i<x.length;i++)

      {

          x[i] *= alpha;

          y[i] *= alpha;

      }

  }

  public static void translate(double[]x,double[]y,double dx,double dy)

  {

      for(int i=0;i<x.length;i++)

      {

          x[i] += dx;

          y[i] += dy;

      }

  }

  public static void rotate(double[] x, double[]y,double theta)

  {

      double rad = Math.toRadians(theta);

      double temp;

      for(int i=0;i<x.length;i++)

      {

          temp = x[i];                           //For storing temporarily the previous value of x before changing so tha it can be used in changing y

          x[i] = x[i]*Math.cos(rad) - y[i]*Math.sin(rad);

          y[i] = y[i]*Math.cos(rad) + temp*Math.sin(rad);  

      }

  }

  public static void main(String args[])

  {

      //This is just implementing you testcase discripted.

      double[]x = new double[4];

      double[]y = new double[4];

      StdDraw.setScale(-5.0, +5.0);

      x = { 0, 1, 1, 0 };

      y = { 0, 0, 2, 1 };

      double alpha = 2.0;

      StdDraw.setPenColor(StdDraw.RED);

      StdDraw.polygon(x, y);

      scale(x, y, alpha);

      StdDraw.setPenColor(StdDraw.BLUE);

      StdDraw.polygon(x, y);

      // Translates polygon by (2, 1).

      StdDraw.setScale(-5.0, +5.0);

      x = { 0, 1, 1, 0 };

      y = { 0, 0, 2, 1 };

      double dx = 2.0, dy = 1.0;

      StdDraw.setPenColor(StdDraw.RED);

      StdDraw.polygon(x, y);

      translate(x, y, dx, dy);

      StdDraw.setPenColor(StdDraw.BLUE);

      StdDraw.polygon(x, y);

      // Rotates polygon 45 degrees.

      StdDraw.setScale(-5.0, +5.0);

      x = { 0, 1, 1, 0 };

      y = { 0, 0, 2, 1 };

      double theta = 45.0;

      StdDraw.setPenColor(StdDraw.RED);

      StdDraw.polygon(x, y);

      rotate(x, y, theta);

      StdDraw.setPenColor(StdDraw.BLUE);

      StdDraw.polygon(x, y);

  }

}

Explanation:

6 0
3 years ago
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