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Bas_tet [7]
2 years ago
6

Figure 22: Find the total yellow area.

Mathematics
1 answer:
Pachacha [2.7K]2 years ago
3 0

Step-by-step explanation:

area of rectangle = l × h

= 9 × y

= 72

9 × y = 72

y = 72÷9

y = 8cm

area of circle = 50.27cm²

total area of the logo = 2(50.27) + 72

= 100.54 + 72

= 172.54cm²

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Claire Drew model of 5/10 explain how Claire could change her model to show how many hundreds are in 5/10 I know this is like my
natta225 [31]

Answer:

There are 0.005 hundreds in 5/10.

Step-by-step explanation:

Claire drew model of 5/10

We want to know how many hundreds are in 5/10.

Let us use an obvious example.

There are three 2's in 6 right?

Suppose we didn't know this, and we are told to find how many 2's are in 6, we get this by representing this in an algebraic expression as:

There are x 2's in 6. This can be written as

2x = 6

Solving for x, by dividing both sides by 2, we have the number of 2's that are in 6.

x = 6/2 = 3.

Now, to our work

We want to find how many hundreds are in 5/10. We solve the equation

100x = 5/10

x = 5/1000 = 0.005

There are 0.005 hundreds in 5/10.

7 0
3 years ago
Arrange the entries of matrix A in increasing order of their cofactors values
givi [52]

To find the cofactor of

A=\left[\begin{array}{ccc}7&5&3\\-7&4&-1\\-8&2&1\end{array}\right]

We cross out the Row and columns of the respective entries and find the determinant of the remaining 2\times 2 matrix with the alternating signs.


Ac_{11}=\left|\begin{array}{ccc}4&-1\\2&1\end{array}\right|


Ac_{11}=4\times 1- -1\times 2


Ac_{11}=4+ 2

Ac_{11}=6




Ac_{12}=-\left|\begin{array}{ccc}-7&-1\\-8&1\end{array}\right|


Ac_{12}=-(-7\times 1- -1\times -8)


Ac_{12}=-(-7- 8)

Ac_{12}=15




Ac_{21}=-\left|\begin{array}{ccc}5&3\\2&1\end{array}\right|


Ac_{21}=-(5\times 1- 3\times 2)


Ac_{21}=-(5-6)


Ac_{21}=1







A_c{23}=-\left|\begin{array}{ccc}7&5\\-8&2\end{array}\right|


Ac_{23}=-(7\times 2 -8\times 5)


Ac_{23}=-(14-40)


Ac_{23}=26




A_c{31}=\left|\begin{array}{ccc}5&3\\4&-1\end{array}\right|


Ac_{31}=5\times -1 -4\times 3


Ac_{31}=-5-12


Ac_{31}=-17


A_c{33}=\left|\begin{array}{ccc}7&5\\-7&4\end{array}\right|


Ac_{33}=7\times 4- -7\times 5


Ac_{33}=28+35


Ac_{33}=63


Therefore in increasing order, we have;

Ac_{31}=-17,Ac_{21}=1,Ac_{11}=6,Ac_{23}=26,Ac_{12}=15, Ac_{33}=63



7 0
3 years ago
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Salsk061 [2.6K]

Answer:

A car can travel 80 miles on 2 gallons of gasoline.

Step-by-step explanation:

8 0
3 years ago
7.875 rounded to the nearest tenth
IRISSAK [1]
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8
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2 years ago
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EASY BRAINLIEST PLEASE HELP!!
iogann1982 [59]

Answer:D..the diagonals bisect each other. Since bisectors divide the diagonals equally in two parts.

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3 years ago
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