There'd be 6 EQUILATERAL triangles in a REGULAR hexagon
This is just simple. For example you have a plane of the form x=a, then you just substitute x with a, and you'll get an equation with y and z only, hence you have a 2-d trace of the intersection. It is just similar for y=b and z=c.
(1) At z=1.5, 2x^2 + 5y^2 + 1.5^2 = 4
2x^2 + 5y^2 = 1.75
Now you have an ellipse in the z=1.5 plane as your trace.
(2) At x=1, 2(1)^2 + 5y^2 + z^2 = 4
5y^2 + z^2 = 2
Now you have an ellipse in the x=1 plane as your trace.
(3) At z=0, 2x^2 + 5y^2 + (0)^2 = 4
2x^2 + 5y^2 = 4
Now you have an ellipse in the z=0 plane as your trace.
(4) At y=0, 2x^2 + 5(0)^2 + z^2 = 4
2x^2 + z^2 = 4
Now you have an ellipse in the y=0 plane as your trace.
1.45
2.135
I believe that's what it should be
Answer:
The number of bananas that Emily bought was 6 and the number of peaches that Emily bought was 8
Step-by-step explanation:
<u><em>The complete question is</em></u>
Emily and her children went into a grocery store and she bought $20.80 worth of bananas and peaches. Each banana costs $0.80 and each peach costs $2. She bought a total of 14 peaches and bananas altogether. Determine the number of peaches and the number of bananas that Emily bought
Let
x ----> the number of bananas that Emily bought
y ----> the number of peaches that Emily bought
we know that
She bought a total of 14 bananas and peaches altogether
so
-----> equation A
She bought $20.80 worth of bananas and peaches
so
-----> equation B
Solve the system by graphing
Remember that the solution is the intersection point both graphs
using a graphing tool
The solution is the point (6,8)
see the attached figure
therefore
The number of bananas that Emily bought was 6 and the number of peaches that Emily bought was 8
The correct answer is A. 3 is in the ones place(3×1) 4 is in the tenths place(4×1/10) 0 is 0, and 5 is in the thousands place (5x1/1000)