Answer:
13.2 miles
Step-by-step explanation:
To solve this, we will need to first solve for the base of the triangle and then use the information we find to solve for the shortest route.
(5.5 + 3.5)² + b² = 15²
9² + b² = 15²
81 + b² = 225
b² = 144
b = 12
Now that we know that the base is 12 miles, we can use that and the 5.5 miles in between Adamsburg and Chenoa to find the shortest route (hypotenuse).
5.5² + 12² = c²
30.25 + 144 = c²
174.25 = c²
13.2 ≈ c
Therefore, the shortest route from Chenoa to Robertsville is about 13.2 miles.
Answer:
The first prime factor we test is 2:
52 / 2 = 26
26 / 2 = 13
13 is a prime number so the prime factorization is
2 * 2 * 13 = 52
Step-by-step explanation:
<span>0.53(3)+5 = 1.59 + 5 = 6.59 when n = 3
</span>0.53(-3)+5 = -1.59 + 5 = 3.41 when n = -3
Alright so after solving it the answer would be x=2 and y= 6
b = - 4
slope m = (0 + 4)/(4 - 0) = 4/4 = 1
equation
y = x - 4
