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den301095 [7]
2 years ago
12

What does the m stand for in the enthalpy equation?

Physics
1 answer:
Morgarella [4.7K]2 years ago
4 0

Answer:

Use the formula ∆H = m x s x ∆T to solve.

Explanation:

Once you have m, the mass of your reactants, s, the specific heat of your product, and ∆T, the temperature change from your reaction, you are prepared to find the enthalpy of reaction. Simply plug your values into the formula ∆H = m x s x ∆T and multiply to solve.

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Consider a cyclotron in which a beam of particles of positive charge q and mass m is moving along a circular path restricted by
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A) v=\sqrt{\frac{2qV}{m}}

B) r=\frac{mv}{qB}

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A)

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\Delta U = qV

where

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where

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v is its final speed

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qV=\frac{1}{2}mv^2

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B)

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F=qvB

where B is the strength of the magnetic field.

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F=m\frac{v^2}{r}

where r is the radius of the orbit.

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C)

The period of revolution of a particle in circular motion is the time taken by the particle to complete one revolution.

It can be calculated as the ratio between the length of the circumference (2\pi r) and the velocity of the particle (v):

T=\frac{2\pi r}{v} (2)

From eq.(1), we can rewrite the velocity of the particle as

v=\frac{qBr}{m}

Substituting into(2), we can rewrite the period of revolution of the particle as:

T=\frac{2\pi r}{(\frac{qBr}{m})}=\frac{2\pi m}{qB}

And we see that this period is indepedent on the velocity.

D)

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The period has been found in part C:

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E)

For this part, we use again the relationship found in part B:

v=\frac{qBr}{m}

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v=\sqrt{\frac{2K}{m}}

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r=\frac{\sqrt{2mK}}{qB}

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Note that for a cyclotron, the acceleration of the particles is achevied in the gap between the dees, where an electric field is applied (in fact, the magnetic field does zero work on the particle, so it does not provide acceleration).

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