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KengaRu [80]
2 years ago
11

2. An electron and a proton are separated by 5 cm:

Physics
1 answer:
Diano4ka-milaya [45]2 years ago
7 0

Answer:

a) the charge of an electron is equivalent to the magnitude of the elementary charge but barring a negative sign since the side of the elementary charge is roughly 1.602 * 10 - 19 Columbus then the charge of the electronic is-1.602 * 10 - 19

b) b=2T on the electron moving in the magnetic field

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Stella [2.4K]

Answer:

gamma rays

Explanation:

8 0
2 years ago
The PV system is operating in a location where the annual average daily incident solar energy (the insolation) on the array equa
vlabodo [156]

The average amount of solar energy incident on the PV per day is 10000 kWh/day.

<h3>Equation</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Let the PV array has an area equal to 50 square meters. Hence:

Average amount of solar energy incident on the PV per day = 200 kWh/m²/day * 50 m² = 10000 kWh/day.

Find out more on Equation at: brainly.com/question/2972832

5 0
2 years ago
Which property of a substance is not affected by physical changes?
Leokris [45]
The answer is A. Reactivity

hope this helps
8 0
3 years ago
How many years would it take to reach the planet saturn travelling at 21 thousand miles per hour? enter your answer with 2 decim
Dmitry_Shevchenko [17]

It would take about 4.8 years to travel from earth to Saturn.

<h3>How long would it take?</h3>

We know that speed is expressed as the ratio of distance to time. In this case, we are trying to know ow many years would it take to reach the planet Saturn travelling at 21 thousand miles per hour.

Given that;

Speed = 21 thousand miles per hour

time taken = ???

Distance = 887 million miles

Speed = distance/time

speed * time = distance

time = distance/speed

time = 8.87 * 10^8 miles/2.1 * 10^4  miles per hour

time = 4.22 * 10^4 hours

If 8.766 * 10^3 hours make 1 year

4.22 * 10^4 hours  make 4.22 * 10^4 hours * 1 year/8.766 * 10^3

= 4.8 years

Learn more about Saturn:brainly.com/question/12181523

#SPJ1

8 0
1 year ago
It is difficult to extinguish a fire on a crude oil tanker, because each liter of crude oil releases 2.80 × 10 7 J of energy whe
boyakko [2]

Answer:

10.4L of water is expended when 1L of crude oil is burned.

Explanation:

This problem requires us to calculate the volume of water that must be expended to absorb the amount of energy released from the burning of 1.00L of crude oil.

In going from water at 18.5°C to steam at 285°C, the water undergoes 3 stages:

Absorption of heat from 18.5°C to 100°C >> phase change to vapour at 100°C >> heating from 100°C to steam at 285°C

Given Cw = 4186 J/kg°C and Cs = 2020 J/kg°C. The latent heat of of vaporization of water Lv = 2.256 ×10⁶ J/kg

The total heat absorbed in the process per kilogram

H = Cw × (100 – 18.5) + Lv + Cs × (285 – 100)

H = 4186 × 81.5 + 2. 256 ×10⁶ + 2020× 185

= 2.696 ×10⁶ J/kg

The amount of heat in J/L of water needed can be calculated as follows:

Density of water = 1000kg/m³ =

1000 kg/m³ × 1m³/1000L = 1kg/L (Basically conversion of density in kg/m³ to kg/L)

Let the volume of water needed be V litres.

Then the mass of water that must be expended = Density × Volume

= 1kg/L × V L = Vkg

The heat that would be absorbed by the water when 1L of crude oil is burned is V×H

= 2.696×10⁶ × V

This is also equal to 2.80×10⁷ J of energy (given).

So,

2.696×10⁶V = 2.8×10⁷

V = (2.80×10⁷)/(2.696×10⁶) = 10.4L of water.

3 0
2 years ago
Read 2 more answers
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