All categories

3 years ago

CAN SOMEONE HELP ME WITH THIS PLEASE AND THANK YOU.

Mathematics

2 answers:

tiny-mole [99]3 years ago

8 0

Answer:

six and one over twelve

Step-by-step explanation:

1/4 + 5 5/6=1/4+35/6 = 6 1/12

vodomira [7]3 years ago

6 0

step 1: 5×6+5
6
step 2: 30+5
6

step 3 35

step 4 answer = 35

You might be interested in

Deon finished his math assignment in 2/5 hours. Then he completed his chemistry assignment in 1/2 hours. How much more time did

ipn [44]

Answer:

Deon spent 1/10 of an hour more on chemistry than on math

Step-by-step explanation:

7 0

3 years ago

Listen just answer I neeed help, but I don’t

adelina 88 [10]

Answer:

look below

Step-by-step explanation:

I'll go in order from top to bottom

$5\frac{2}{3}$

$1\frac{5}{9}$

$6\frac{1}{2}$

$6\frac{1}{3}$

$5\frac{1}{2}$

5 0

3 years ago

Thanks for helping, I appreciate it!

timofeeve [1]

14. 5
15. 2
16. -10
17. -3
18. 1
19. -20

4 0

3 years ago

Read 2 more answers

What is the solution set for | s+4 | = 6?

saveliy_v [14]

Answer:

s=2,−10

Step-by-step explanation:

Find all solutions for s by breaking the absolute value into the positive and negative components.

4 0

1 year ago

An article presents measures of penetration resistance for a certain fine-grained soil. Fifteen measurements, expressed as a mul

balu736 [363]

Answer:

$2.64-2.14\frac{1.32}{\sqrt{15}}=1.911$

$2.64+2.14\frac{1.32}{\sqrt{15}}=3.369$

So on this case the 95% confidence interval would be given by (1.911;3.37)

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=2.64$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=1.32 represent the sample standard deviation

n=15 represent the sample size

Solution to the problem

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=15-1=14$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,14)".And we see that $t_{\alpha/2}=2.14$

Now we have everything in order to replace into formula (1):

$2.64-2.14\frac{1.32}{\sqrt{15}}=1.911$

$2.64+2.14\frac{1.32}{\sqrt{15}}=3.369$

So on this case the 95% confidence interval would be given by (1.911;3.37)

6 0

3 years ago