Answer: If we define 2:00pm as our 0 in time; then:
at t= 0. the velocity is 30 mi/h.
then at t = 10m (or 1/6 hours) the velocity is 50mi/h
Then, if we think in the "mean acceleration" as the slope between the two velocities, we can find the slope as:
a= (y2 - y1)/(x2 - x1) = (50 mi/h - 30 mi/h)/(1/6h - 0h) = 20*6mi/(h*h) = 120mi/
Now, this is the slope of the mean acceleration between t= 0h and t = 1/6h, then we can use the mean value theorem; who says that if F is a differentiable function on the interval (a,b), then exist at least one point c between a and b where F'(c) = (F(b) - F(a))/(b - a)
So if v is differentiable, then there is a time T between 0h and 1/6h where v(T) = 120mi/
He just switched sides of the variables and numbers. Instead if adding the opposite.
Answer:
c)
Step-by-step explanation:
For a function the value of the variable "x" must correspond to a single value of "y"
Hope this helps
Answer:
i think you should look up a yt video to see how to do it lol
Step-by-step explanation:
Answer:
This is a classical problem which has delighted calculus students down through the ages.
We first express the volume of the box as a function of x, the side of the square which is cut out of each corner.
The resulting box will have a base which is a square which all of whose sides will have length 12 - 2x. The height of the box will be x. Therefore, the volume will be
V = (12 - 2x)2x
= 144x - 48x2 + 4x3
Step-by-step explanation:
hope this helps
