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3 years ago

What is the solution to the system of equations?

Mathematics

1 answer:

MariettaO [177]3 years ago

7 0

Answer:

x=-4 y=-1

Step-by-step explanation:

Let's solve your system by substitution.

−3x−8y=20;y=5x+19

Rewrite equations:

y=5x+19;−3x−8y=20

Step: Solve y=5x+19for y:

y=5x+19

Step: Substitute5x+19foryin−3x−8y=20:

−3x−8y=20

−3x−8(5x+19)=20

−43x−152=20(Simplify both sides of the equation)

−43x−152+152=20+152(Add 152 to both sides)

−43x=172

−43x

−43

172

−43

(Divide both sides by -43)

x=−4

Step: Substitute−4forxiny=5x+19:

y=5x+19

y=(5)(−4)+19

y=−1(Simplify both sides of the equation)

Answer:

x=−4 and y=−1

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4 years ago

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3 years ago

Find the root(s) of f (x) = (x + 5)3(x - 9)2(x + 1). -5 with multiplicity 3 5 with multiplicity 3 -9

faust18 [17]

Answer:

-5, multiplicity 3; +9, multiplicity 2; -1

Step-by-step explanation:

The roots of f(x) are those values of x that make the factors be zero. For a factor of x-a, the root is x=a, because a-a=0. If the factor appears n times, then the root has multiplicity n.

f(x) = (x+5)^3(x-9)^2(x+1) has roots ...

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3 years ago

Where did we get one?

77julia77 [94]

Answer:

The -1 came from factoring.

The equation is multiplied by 8 because 8 could be pulled from 16x-8.

16 can be divided by 8 2 times and 8 can only divided by 8 once.

so factoring it makes the equation 8(2x-1)

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3 years ago

Researchers study the relationship between interpersonal violence and health in college age women. The selected an alpha of 0.05

Lina20 [59]

Answer:

Explained below.

Step-by-step explanation:

A statistical hypothesis test is being performed to determine whether there was a significant difference in the type of primary residence (home vs. student housing) for abused versus non abused college aged women.

The hypothesis can be defined as:

H₀: There is no difference in the type of primary residence or abused versus non abused college aged women.

Hₐ: There is a significant difference in the type of primary residence or abused versus non abused college aged women.

The significance level of the test is:

α = 0.05

The computed p-value is:

p-value = 0.35

p-value = 0.35 > α = 0.05

The null hypothesis will not be rejected.

The p-value is inversely related to the sample size of the test.

That is, larger the sample size smaller is the p-value and smaller the sample size larger is the p-value.

A p-value of 0.35 is very large and unusual. This can happen because of the inadequate sample size selected.

As the p-value indicates an unusual result, it can be said that an error has been made while concluding that the null hypothesis is true, when in fact it is not.

This type of error is known as the type II error.

The correct decision should be:

There is a statistically significant difference in the type of primary residence for abused vs. non-abused college aged women.

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3 years ago