Answer:
2 - √3
Step-by-step explanation:
tan45 = 1
tan60 = √3
2 tan 45 - tan 60
2(1) - √3
=> 2 - √3
Hello!
We know that, in terms of radians and degrees, that an angle that turns through the entirety of a circle is 360 degrees. To find 1/3 of it, we just multiply by 1/3.
360(1/3)=120
Therefore, our answer is 120°.
I hope this helps!
Answer:
1/12 + 1/2 = 1/12 + 6/12 - 1+6/12 = 7/12
Step-by-step explanation:
hope this makes sense
Answer:
![x_1 =2 , x_2=7](https://tex.z-dn.net/?f=x_1%20%3D2%20%2C%20x_2%3D7)
Step-by-step explanation:
Consider the revenue function given by
. We want to find the values of each of the variables such that the gradient( i.e the first partial derivatives of the function) is 0. Then, we have the following (the explicit calculations of both derivatives are omitted).
![\frac{dR}{dx_1} = -10x_1-2x_2+34 =0](https://tex.z-dn.net/?f=%5Cfrac%7BdR%7D%7Bdx_1%7D%20%3D%20-10x_1-2x_2%2B34%20%3D0)
![\frac{dR}{dx_2} = -16x_2-2x_1+116 =0](https://tex.z-dn.net/?f=%5Cfrac%7BdR%7D%7Bdx_2%7D%20%3D%20-16x_2-2x_1%2B116%20%3D0)
From the first equation, we get,
.If we replace that in the second equation, we get
![-16\frac{-10x_1+34}{2} -2x_1+116=0= 80x_1-2x_1+116-272= 78x_1-156](https://tex.z-dn.net/?f=-16%5Cfrac%7B-10x_1%2B34%7D%7B2%7D%20-2x_1%2B116%3D0%3D%2080x_1-2x_1%2B116-272%3D%2078x_1-156)
From where we get that
. If we replace that in the first equation, we get
![x_2 = \frac{-10\cdot 2 +34}{2}=\frac{14}{2} = 7](https://tex.z-dn.net/?f=x_2%20%3D%20%5Cfrac%7B-10%5Ccdot%202%20%2B34%7D%7B2%7D%3D%5Cfrac%7B14%7D%7B2%7D%20%3D%207)
So, the critical point is
. We must check that it is a maximum. To do so, we will use the Hessian criteria. To do so, we must calculate the second derivatives and the crossed derivatives and check if the criteria is fulfilled in order for it to be a maximum. We get that
![\frac{d^2R}{dx_1dx_2}= -2 = \frac{d^2R}{dx_2dx_1}](https://tex.z-dn.net/?f=%20%5Cfrac%7Bd%5E2R%7D%7Bdx_1dx_2%7D%3D%20-2%20%3D%20%5Cfrac%7Bd%5E2R%7D%7Bdx_2dx_1%7D)
![\frac{d^2R}{dx_{1}^2}=-10, \frac{d^2R}{dx_{2}^2}=-16](https://tex.z-dn.net/?f=%5Cfrac%7Bd%5E2R%7D%7Bdx_%7B1%7D%5E2%7D%3D-10%2C%20%5Cfrac%7Bd%5E2R%7D%7Bdx_%7B2%7D%5E2%7D%3D-16)
We have the following matrix,
.
Recall that the Hessian criteria says that, for the point to be a maximum, the determinant of the whole matrix should be positive and the element of the matrix that is in the upper left corner should be negative. Note that the determinant of the matrix is
and that -10<0. Hence, the criteria is fulfilled and the critical point is a maximum