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3 years ago

Which polynomial is a binomial?

Mathematics

1 answer:

Aleksandr-060686 [28]3 years ago

7 0

A is a binomial since it has only 2 values

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Steve reaches into a bag with 5 marbles 3 yellow marbles and 2 green marbles and randomly selects one the he puts the marble bac

Bezzdna [24]

Answer:

Independent

Step-by-step explanation:

The reliance of an event on the outcine of another event gives rise to a dependent event. For any two or more event, whereby the outcome of event A has no effect on the possible outcome of event B, then such scenario is termed as being Independent. In the scenario described above, the outcome oof Sam's pick does not depend on the outcine of Steve's pick. This is because, once Steve makes his selection, the marble is returned into the box before Sam makes his own selection.Therefore, no matter the color of marble picked by Steven, it will have no bearing on the outcome of Sam's pick.

5 0

3 years ago

The rectangle shown has a perimeter of 54 cm and the given area. Its length is 3 more than 3 times its width. Write and solve a

algol13

Answer:

Step-by-step explanation:

the perimeter P=2(L+W)=54

P=2L+2W=54 OR L+W=27

we know that L=3W+3

P=3W+W=27-3

4W=24

W=6 CM

L=21CM

5 0

3 years ago

Given the function k(t) = 6t − 9,<br> complete the following Solve k(t) = 21.

ELEN [110]

Answer: 5(k)

Step-by-step explanation: “k”times “t” equals 6t-9 so if “k” times “t” equals 21, 6t-9=21, add 9 to 21 which equals 30 so then you divide 30 by 6 to get 5. “t”=5 which means the solution is 5(k)

(I’m just a sixth grader dont blame me if I couldn’t do this)

7 0

3 years ago

The following data set represents the age of

Julli [10]

$\huge\text{Hey there!}$

$\huge\textsf{Breaking the meaning down in simpler terms}$
$\huge\textbf{Median:}\\\large\text{is understood to be \bf the number in the center (also known as}\\\large\textbf{the middle number)}$

$\huge\textbf{Mean:}\\\large\text{is understood to be the \bf total.}$

$\huge\textsf{Formulas for each term}$

$\huge\text{Median:}\\\large\textsf{To find the median you have to put each of your numbers in your data}\\\large\textsf{set from LEAST (smallest) to GREATEST (biggest). }$

$\huge\text{Mean:}\\\mathsf{\dfrac{sum\ of\ all\ terms}{number\ of\ terms}= mean}$

$\huge\textbf{SOLVING FOR THE QUESTION}$

$\huge\textsf{Median:}\\\\\large\textbf{Original data set: }\large\text{27, 52, 64, 41, 33, 38, 42, 60, 72, 68}\\\\\large\textbf{Conversion: }\large\text{27, 33, 38, 41, 42, 52, 64, 68, 72}\\\\\large\textsf{Make sure it is even between both sides of the data plot.}\\\\\large\text{It seems to even on BOTH sides of \boxed{\textsf{14}} so it could possibly be your}\\\large\text{median.}$

$\huge\textsf{Mean:}\\\\\large\textbf{Original data set: }\large\text{27, 52, 64, 41, 33, 38, 42, 60, 72, 68}\\\\\large\textsf{Your equation: }\mathsf{\dfrac{27 + 52 + 64 + 41 + 33 + 38 + 42 + 60 +72 + 68}{10}}\\\\\mathsf{\dfrac{79 + 64 + 41 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{143 + 41 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{184 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{217 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{255 + 42 + 60 + 72 + 68}{10}}$

$\mathsf{\dfrac{297 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{357 + 72 + 68}{10}}\\\\\mathsf{\dfrac{429 + 68}{10}}\\\\\mathsf{\dfrac{497}{10}}\\\\\mathsf{\approx 49.70}\\\\\large\text{From the looks of it \boxed{\rm{\dfrac{497}{10}}}\ or \boxed{\text{49.70}} could possibly be your mean.}$