Find smallest number which on adding to 19 it is exactly divisible by 28,36 and 45 (LCM).

Mathematics

1 answer:

BabaBlast [244]1 year ago

7 0

Answer:

1241

Step-by-step explanation:

∴

L.C.M. of 28, 36 and 45 = 2 × 2 × 3 × 3 × 5 × 7 = 1260

∴

the required number is 1260 - 19 = 1241

Hence, if we add 19 to 1241 we will get 1260 which is exactly divisible by 28, 36 and 45.

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