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Andreas93 [3]
3 years ago
13

1. What is the value of x?

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
7 0

Answer:

d and ef

Step-by-step explanation:

efwfnhew'foehfnwekf;esf

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Allied Corporation is trying to sell its new machines to Ajax. Allied claims that the machine will pay for itself since the time
kvasek [131]

Answer:

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

Step-by-step explanation:

We must evaluate the differences of the means of the two machines, to do so, we will assume a CI  of 95%, and as the interest is to find out if the new machine has better performance ( machine has a bigger efficiency or the new machine produces more units per unit of time than the old one) the test will be a one tail-test (to the left).

New machine

Sample mean                  x₁ =    25

Sample variance               s₁  = 27

Sample size                       n₁  = 45

Old machine

Sample mean                    x₂ =  23  

Sample variance               s₂  = 7,56

Sample size                       n₂  = 36

Test Hypothesis:

Null hypothesis                         H₀             x₂  -  x₁  = d = 0

Alternative hypothesis             Hₐ            x₂  -  x₁  <  0

CI = 90 %  ⇒  α =  10 %     α = 0,1      z(c) = - 1,28

To calculate z(s)

z(s)  =  ( x₂  -  x₁ ) / √s₁² / n₁  +  s₂² / n₂

s₁  = 27     ⇒    s₁²  =  729

n₁  = 45    ⇒   s₁² / n₁    = 16,2

s₂  = 7,56   ⇒    s₂²  = 57,15

n₂  = 36     ⇒    s₂² / n₂  =  1,5876

√s₁² / n₁  +  s₂² / n₂  =  √ 16,2  + 1.5876    = 4,2175

z(s) = (23 - 25 )/4,2175

z(s)  =  - 0,4742

Comparing z(s) and  z(c)

|z(s)| < | z(c)|  

z(s) is in the acceptance region. We accept H₀  we did not find a significantly difference in the performance of the two machines therefore we suggest not to buy a new machine

The very hight dispersion of values s₁ = 27 is evidence of frecuent values quite far from the mean

3 0
3 years ago
Please help! i do not understand !
cluponka [151]

Answer:

C

Step-by-step explanation:

Know that two angles added equals 180

3 0
3 years ago
Read 2 more answers
given the following linear function sketch the graph of the function and find the domain and range. f(x)=-5x+4
velikii [3]

It's a linear function. We need only two points to sketch the graph.

f(x) = -5x + 4 → y = -5x + 4

for x = 0 → y = -5(0) + 4 = 0 + 4 = 4 → (0, 4)

for x = 1 → y= -5(1) + 4 = -5 + 4 = -1 → (1, -1)

The domain and the range is the set of all real numbers.

5 0
3 years ago
What’s the correct answer for this question?
Helen [10]

Answer:

( -1 , 1 )

Step-by-step explanation:

(x1,y1) = (5,9)

(x2,y2) = (-7,-7)

=(-7+5/2 , -7+9/2)

= (-1,1)

3 0
3 years ago
A club is choosing 2 members to serve on a committee. The club has nominated 2 women and 4 men. Based on chance alone, what is t
tekilochka [14]

Answer:

53.33% probability that one woman and one man will be chosen to be on the committee

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

The order in which the members are chosen is not important, so we use the combinations formula to solve this question.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

What is the probability that one woman and one man will be chosen to be on the committee?

Desired outcomes:

One woman, from a set of 2, and one man, from a set of 4. So

D = C_{2,1}*C_{4,1} = \frac{2!}{1!1!}*\frac{4!}{1!3!} = 8

Total outcomes:

Two members from a set of 2 + 4 = 6. So

T = C_{6,2} = \frac{6!}{2!4!} = 15

Probability:

p = \frac{D}{T} = \frac{8}{15} = 0.5333

53.33% probability that one woman and one man will be chosen to be on the committee

5 0
3 years ago
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