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trasher [3.6K]
3 years ago
12

the seventh and eighth grade bands held a joint concert. together there was 188 band members. if the eight grade band is 3 times

as big as the seventh grade band, how big is the eight grade
Mathematics
2 answers:
Montano1993 [528]3 years ago
4 0
8th grade = 3x = 3(47) = 141 band members.

7th + 8th = 188

7th = x
8th = 3x

x + 3x = 188    ; x = 47 ;  47 + 3(47) = 47 + 141 = 188
4x = 188
4x / 4 = 188 / 4
x = 47 --> 7th grade

8th grade = 3x = 3(47) = 141

To check:
x + 3x = 188    ; x = 47 ;
47 + 3(47) = 188
47 + 141 = 188
188 = 188



Ipatiy [6.2K]3 years ago
4 0
Let the size of the seventh grade band be s
That means the size of the eighth grade band must be 3s because it is 3 times as big as the seventh grade band.
Combined, the two bands have 188 members.
3s and s combined is 4s. Thus 4s must equal 188.

4s = 188
s= 47
3s = 141

The eighth grade band has 141 members.
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The downtown sample has a proportion of

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The average of proportion is:

p=\frac{n_1p_1+n_2p_2}{n_1+n_2}=\frac{60*0.60+50*0.62}{60+50}=\frac{67}{110}=0.61

The standard deviation of the difference of proportions is:

s_{p1-p2}=\sqrt{\frac{p(1-p)}{n_1} +\frac{p(1-p)}{n_2} } =\sqrt{\frac{0.61*0.39}{60} +\frac{0.61*0.39}{50} }\\\\s_{p1-p2}=\sqrt{0.003965+0.004758}=0.0934

Then, we can calculate the value of the statistic z

z=\frac{p_1-p_2}{s}=\frac{0.60-0.62}{0.0934}=\frac{-0.02}{0.0934} =  0.214

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<h3>How to solve for the value of n</h3>

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The least common multiple allows us to know what is the smallest number that is a multiple of a certain set of numbers.

One procedure for calculating the least common multiple is to break each number into prime factors. Then the common and uncommon factors are raised to the highest exponent, which must be multiplied.

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To calculate the smallest number of packages of each they can buy, you calculate the least common multiple.

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