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son4ous [18]
3 years ago
15

Which number has the highest value -11 or 7

Mathematics
1 answer:
lana66690 [7]3 years ago
7 0

Answer:

7

Step-by-step explanation:

-11 is negative and 7 is positive. Positive numbers have greater values than negative numbers.

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PLEASE HELP I WILL LOVE YOU FOREVER
Aleksandr-060686 [28]

Answer:

9 16-ounce packages

Step-by-step explanation:

144oz. ÷ 16 = 9 Packages

8 0
2 years ago
How do you do this Problem using factoring (fx)=4x^2-25?
Yanka [14]

Answer: (2x+5)(2x−5)

Step-by-step explanation:For me, what i like to do is to try divide the problem into two parts. For example in this problem, you would divide the 4x^2 into two 4x(since 4x+4x = 4x^2). Then 25 can be divide into into 5s (5x5=25). SInce you know that its a negative 25, you know that it has to be a negative on one of the sides. So the answer in factor form is (2x+5)(2x−5)

5 0
3 years ago
Experiment with different types of polygons, such as a triangle, rectangle, parallelogram, pentagon, hexagon, and so on, and rev
Troyanec [42]

Answer:

Polygon 1Axis of Rotation 2Solid of Revolution

irregular pentagon :

  • 1axis of symmetry
  • 2diamond-shaped solid

right triangle:

  • 1hypotenuse
  • 2two cones with a common circular base

Step-by-step explanation:

PLATO hope this helps

4 0
3 years ago
Trey’s car has a 20-gallon fuel tank. The fuel gauge points to ¼ . If Trey buys 10 gallons of gas, what will be the new reading
Lelu [443]

Answer:

3/4

Step-by-step explanation:

1/4 + 2/4 = 3/4


5 + 10 = 15

6 0
3 years ago
Read 2 more answers
Imagine that you need to compute e^0.4 but you have no calculator or other aid to enable you to compute it exactly, only paper a
labwork [276]

Answer:

0.0032

Step-by-step explanation:

We need to compute e^{0.4} by the help of third-degree Taylor polynomial that is expanded around at x = 0.

Given :

e^{0.4} < e < 3

Therefore, the Taylor's Error Bound formula is given by :

$|\text{Error}| \leq \frac{M}{(N+1)!} |x-a|^{N+1}$   , where $M=|F^{N+1}(x)|$

         $\leq \frac{3}{(3+1)!} |-0.4|^4$

         $\leq \frac{3}{24} \times (0.4)^4$

         $\leq 0.0032$

Therefore, |Error| ≤ 0.0032

4 0
3 years ago
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