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igor_vitrenko [27]
2 years ago
10

Mr. Adeb takes out an $8,000 personal loan to restore his antique car. The bank loans him the money at 4.5% simple interest for

4 years.
a. How much will Mr. Adeb pay in interest? _

b. What is the total cost of the restoration including the interest? _

Mr. Adeb takes out an $8,000 personal loan to restore his antique car. The bank loans him the money at 4.5% simple interest for 4 years.

a. How much will Mr. Adeb pay in interest?

b. What is the total cost of the restoration including the interest?
Mathematics
1 answer:
MariettaO [177]2 years ago
7 0

Answer:

A) $1440

B) $9440

Step-by-step explanation:

A) 4.5% x $8000 = $360 x 4 years = $1440

B) $1440 + $8000 = $9440

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A park in a subdivision has a triangular shape. Two adjacent sides of the park are 533 feet and 525 feet. The angle between the
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<span>Two adjacent sides of the park say x and y are,
</span><span>x=533feet
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A=53º
area=1/2*b*c*sin(A)
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3 years ago
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The figure shown below is composed of a semicircle and a non-overlapping equilateral triangle and contains a hole that is also c
Sloan [31]

Check the picture below.

since we know the radius of the larger semicircle is 8, thus its diameter is 16, which is the length of one side of the equilateral triangle.  We also know the smaller semicircle has a radius of 1/3, and thus a diameter of 2/3, namely the lenght of one side of the small equilateral triangle.

now, if we just can get the area of the larger figure and the area of the smaller one and subtract the smaller from the larger, we'll be in effect making a hole/gap in the larger and what's leftover is the shaded figure.

\bf \stackrel{\textit{area of a semi-circle}}{A=\cfrac{1}{2}\pi r^2\qquad r=radius}~\hspace{10em}\stackrel{\textit{area of an equilateral triangle}}{A=\cfrac{s^2\sqrt{3}}{4}\qquad s=\stackrel{side's}{length}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{\Large Areas}}{\left[ \stackrel{\textit{larger figure}}{\cfrac{1}{2}\pi 8^2~~+~~\cfrac{16^2\sqrt{3}}{4}} \right]\qquad -\qquad \left[ \cfrac{1}{2}\pi \left( \cfrac{1}{3} \right)^2 +\cfrac{\left( \frac{2}{3} \right)^2\sqrt{3}}{4}\right]}

\bf \left[ 32\pi +64\sqrt{3} \right]\qquad -\qquad \left[ \cfrac{\pi }{18}+\cfrac{\frac{4}{9}\sqrt{3}}{4} \right] \\\\\\ \left[ 32\pi +64\sqrt{3} \right]\qquad -\qquad \left[ \cfrac{\pi }{18}+\cfrac{\sqrt{3}}{9} \right]~~\approx~~ 211.38 - 0.37~~\approx~~ 211.01

3 0
4 years ago
The high for yesterday was 90°F, today the high is 78°F. What is the percent decrease in the
Sati [7]

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The temperature from yesterday to today decreased by 12 degrees fahrenheit.

Step-by-step explanation:

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3 years ago
Study the Proof Given.
andrezito [222]
Given that B is the midpoint of line AC and line BC is congruent to line DE.

The following statements and reasons, proves that line AB is congruent to line DE.

     Statement                                                   Reasons

1.  B is the midpoint of line AC                        Given
2.  Line AB is congruent to line BC.                 Midpoint of a line segment
3.  Line BC is congruent to line DE                  Given
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3 years ago
Which transformation will map an isosceles trapezoid onto itself? rotation by 180° about its center, reflection across a diagona
alukav5142 [94]

Answer:

The correct option is 4.

Step-by-step explanation:

The non parallel sides of an isosceles trapezoid are congruent.

The image of an isosceles trapezoid is same as the preimage of isosceles trapezoid if

1. Reflection across a line joining the midpoints of parallel sides.

2. Rotation by 360° about its center.

3. Rotation by 360° about origin.

If we rotate the trapezoid by 180° about its center, then the parallel sides will interchanged.

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After rotation by 360° about the center, we always get an onto figure.

Therefore option 4 is correct.

6 0
3 years ago
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