Answer:
The position of the first dark spot on the positive side of the central maximum is 1.26 mm.
Explanation:
Given that,
Wavelength of light is 633 nm.
Slit width, d = 0.5 mm
The diffraction pattern forms on a screen 1 m away from the slit. We need to find the position of the first dark spot on the positive side of the central maximum.
For destructive interference :
Y is the distance of the minima from central maximum
Here, n = 1
So, the position of the first dark spot on the positive side of the central maximum is 1.26 mm.