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Darina [25.2K]
3 years ago
10

Pls help pls help pls help

Mathematics
2 answers:
rosijanka [135]3 years ago
6 0

Answer:

tubol mo mabaho kaya 1 too 5 so it means 5 days ka sa cr nag tutubol, ok <u>i</u><u> </u><u>hope</u><u> </u><u>it</u><u> </u><u>helps</u><u> </u><u>its</u><u> </u><u>the</u><u> </u><u>grett</u><u> </u><u>answer</u><u> </u><em> </em><em>do</em><em> </em><em>it</em><em> </em><em>in</em><em> </em><em>your</em><em> </em><em>solution</em><em> </em><em>paper</em><em> </em><em>or</em><em> </em><em /><em>computers</em>

Flauer [41]3 years ago
3 0

Answer:

the answer is Y=5x

Step-by-step explanation:

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Step-by-step explanation:

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A certain bridge arch is in the shape of half an ellipse 106 feet wide and 33.9 feet high. At what horizontal distance from the
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Step-by-step explanation:

The equation of an ellipse is equal to:

\frac{x^2}{a^{2} } +\frac{y^2}{b^{2} } =1

Where a is the half of the wide, b is the high of the ellipse, x is the horizontal distance from the center and y is the height of the ellipse at that distance.

Then, replacing a by 106/2 and b by 33.9, we get:

\frac{x^2}{53^{2} } +\frac{y^2}{33.9^{2} } =1\\\frac{x^2}{2809} +\frac{y^2}{1149.21} =1

Therefore, the horizontal distances from the center of the arch where the height is equal to 12.3 feet is calculated replacing y by 12.3 and solving for x as:

\frac{x^2}{2809} +\frac{y^2}{1149.21} =1\\\frac{x^2}{2809} +\frac{12.3^2}{1149.21} =1\\\\\frac{x^2}{2809}=1-\frac{12.3^2}{1149.21}\\\\x^{2} =2809(0.8684)\\x=\sqrt{2809(0.8684)}\\x=49.3883

So, the horizontal distance from the center is 49.3883 feet

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Answer:

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Step-by-step explanation:

hope this helps

6 0
3 years ago
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