Help me solve this thing por favor i only came for the answers

The area of a rectangular wall of a barn is 144 square feet. Its length is 10 feet longer than the width. Find the length and wi

denpristay [2]

Answer:

8 feet

Step-by-step explanation:

Let l and w be length and width, respectively. Then:

lw=144 and

l=w+10

So:

w(w+10)=144

w²+10w-144=0

(w+18)(w-8)=0

w=8 as the width ................

3 0

2 years ago

What’s 4/5 divided by 3

Valentin [98]

Answer:

$\frac{4}{15}$

Step-by-step explanation:

remember when dividing with fractions, you are multiplying by the reciprocal.

this means

$\frac{4}{5} \div3=\frac{4}{5}*\frac{1}{3}=\frac{4}{15}$

6 0

3 years ago

Read 2 more answers

The wingspans of Rodrigues fruit bats are normally distributed, with a mean of 82.5 centimeters and a standard deviation of 2.5

IrinaK [193]

81.5%
i honestly looked at the numbers in the problem

6 0

3 years ago

deion has a 3/4 pound bag of dog treats. he will give his dog 1/8 of the treats after they play each day. how many will the bag

tester [92]

It will last 6 days because 3/4 is equal to 6/8 so 1/8 x _=6/8. The missing number is 6 which is 6 days

6 0

3 years ago

Minor surgery on horses under field conditions requires a reliable short-term anesthetic producing good muscle relaxation, minim

andreev551 [17]

Answer:

$p_v =P(t_{74}$

If we compare the p value and a significance level for example $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.

Step-by-step explanation:

Data given and notation

$\bar X=18.81$ represent the average lateral recumbency for the sample

$s=8.4$ represent the sample standard deviation

$n=75$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to apply a left tailed test.

What are H0 and Ha for this study?

Null hypothesis: $\mu \geq 20$

Alternative hypothesis : $\mu < 20$

Compute the test statistic

The statistic for this case is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{18.81-20}{\frac{8.4}{\sqrt{75}}}=-1.227$

The degrees of freedom are given by:

$df=n-1=75-1=74$

Give the appropriate conclusion for the test

Since is a one side left tailed test the p value would be:

$p_v =P(t_{74}$

Conclusion

If we compare the p value and a significance level for example $\alpha=0.1$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, so we can conclude that the true mean it's not significantly less than 20 min.

3 0

3 years ago